1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Solnce55 [7]
3 years ago
9

bob has 64 cups. could he distribute them into 6 equally in stacks and not have any left over? Explain

Mathematics
1 answer:
Iteru [2.4K]3 years ago
8 0

Bob cannot distribute the cups in six equal stacks and not have any left over.

Step-by-step explanation:

In order to divide the total number of cups in six equal stacks with no left over, the total number of cups will be divided by 6, if there is any remainder then the cups cannot be equally divided with no left over.

So

Dividing 64 by 6

= \frac{64}{6} \\= 10\frac{4}{6}

Here

Quotient = 10

Remainder = 4

As there are 4 cups left, Bob cannot distribute the cups in six equal stacks and not have any left over.

Keywords: Division, fractions

Learn more about division at:

  • brainly.com/question/4464845
  • brainly.com/question/4522984

#LearnwithBrainly

You might be interested in
What best describes index fossils
KonstantinChe [14]

Answer:

Index fossil, any animal or plant preserved in the rock record of the Earth that is characteristic of a particular span of geologic time or environment. A useful index fossil must be distinctive or easily recognizable, abundant, and have a wide geographic distribution and a short range through time.

Step-by-step explanation:

6 0
3 years ago
Evaluate the integral. W (x2 y2) dx dy dz; W is the pyramid with top vertex at (0, 0, 1) and base vertices at (0, 0, 0), (1, 0,
In-s [12.5K]

Answer:

\mathbf{\iiint_W (x^2+y^2) \ dx \ dy \ dz = \dfrac{2}{15}}

Step-by-step explanation:

Given that:

\iiint_W (x^2+y^2) \ dx \ dy \ dz

where;

the top vertex = (0,0,1) and the  base vertices at (0, 0, 0), (1, 0, 0), (0, 1, 0), and (1, 1, 0)

As such , the region of the bounds of the pyramid is: (0 ≤ x ≤ 1-z, 0 ≤ y ≤ 1-z, 0 ≤ z ≤ 1)

\iiint_W (x^2+y^2) \ dx \ dy \ dz = \int ^1_0 \int ^{1-z}_0 \int ^{1-z}_0 (x^2+y^2) \ dx \ dy \  dz

\iiint_W (x^2+y^2) \ dx \ dy \ dz = \int ^1_0 \int ^{1-z}_0 ( \dfrac{(1-z)^3}{3}+ (1-z)y^2) dy \ dz

\iiint_W (x^2+y^2) \ dx \ dy \ dz = \int ^1_0  \ dz \  ( \dfrac{(1-z)^3}{3} \ y + \dfrac {(1-z)y^3)}{3}] ^{1-x}_{0}

\iiint_W (x^2+y^2) \ dx \ dy \ dz = \int ^1_0  \ dz \  ( \dfrac{(1-z)^4}{3}+ \dfrac{(1-z)^4}{3}) \ dz

\iiint_W (x^2+y^2) \ dx \ dy \ dz =\dfrac{2}{3} \int^1_0 (1-z)^4 \ dz

\iiint_W (x^2+y^2) \ dx \ dy \ dz =- \dfrac{2}{15}(1-z)^5|^1_0

\mathbf{\iiint_W (x^2+y^2) \ dx \ dy \ dz = \dfrac{2}{15}}

7 0
3 years ago
What is greater than one in 5 1/2
Ira Lisetskai [31]
I think 6 1/2,but I could be wrong so take that with a grain of salt
5 0
3 years ago
Comparing to Internet service plans plan one cost $34.99 per month plan to cost $134.97 every three months if Crystal plans to s
Ket [755]
Plan 1 because she spends 435.88 more if she goes with plan 2
5 0
3 years ago
You just hung a picture twelve inches above the wall trim.
GenaCL600 [577]
Yes I sure did hang the picture what about it
4 0
2 years ago
Other questions:
  • 2. Solve 9 = 1 + 8x – 8. A. x = 2 B. x = 10
    7·2 answers
  • I need to find the circumference and area of a circle with a diameter of 20 cm
    13·1 answer
  • The perimeter of a basketball court is 90 m in the length is 6 m longer than twice the with what are the length and with
    14·1 answer
  • Solve each inequality. Graph and check the solution.
    12·1 answer
  • 2) a) What is special about the temperature 100 °C?
    6·1 answer
  • Write the product as a trinomial.
    9·1 answer
  • I don't think this is correct plz check me
    9·1 answer
  • What is the slope of the graph shown below? ​
    12·2 answers
  • Solve:<br><br> Picture attached
    11·2 answers
  • In 2016, a maglev train in Japan traveled 1.1 miles in 1045 seconds.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!