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3 years ago

Use 2 points to write an equation for each function. Exponential functions.

Mathematics

1 answer:

8_murik_8 [283]3 years ago

6 0

$y=ma^x\\\\(0;\ 10)\to m\cdot a^0=10\to m=10\\\\y=10a^x\\\\(1;\ 20)\to 10a^1=20\ \ \ |:10\\a=2\\\\\boxed{y=20\cdot2^x}\\\\check:\\(-2;\ 2.5)\to2.5=10\cdot2^{-2}\\\\2.5=10\cdot\dfrac{1}{2^2}\\\\2.5=10\cdot\dfrac{1}{4}\\\\2.2=2.2\ correct\ :)\\\\(2;\ 40)\to40=10\cdot2^2\\\\40=10\cdot4\\\\40=40$

Answer: $\boxed{y=10\cdot2^x}$

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The question: a computer manufacturer built a new facility for assembling computers. there were construction and new equipment c

DiKsa [7]

Answer:

The equation that closely represents the graph is $\mathbf{y=60x-160}$

Option A is correct.

Step-by-step explanation:

We need to find equation that represents the graph.

We can write equation in slope-intercept form: $y=mx+b$ where m is slope and b is y-intercept.

For finding the equation we need to find slope and y-intercept

Finding slope

The slope can be found using formula: $Slope=\frac{y_2-y_1}{x_2-x_1}$

From the graph we can find $x_1=0, y_1=-160, x_2=1, y_2=-100$

Putting values and finding slope

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{-100-(-160)}{1-0} \\Slope=\frac{-100+160}{1}\\Slope=-100+160\\Slope=60$

We get Slope = 60

Finding y-intercept

Using point (0,-160) and slope m = 60, we can find y-intercept

$y=mx+b\\-160=60(0)+b\\b+0=-160\\b=-160$

Writing the equation

So, the equation for given graph having slope m = 60 and y-intercept b =-160 is:

$y=mx+b\\y=60(x)+(-160)\\y=60x-160$

So, The equation that closely represents the graph is $\mathbf{y=60x-160}$

Option A is correct.

7 0

3 years ago

7 3 2 = 2 insert symbols

san4es73 [151]

Answer:

7 - 3 - 2 = 2

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

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VikaD [51]

All real numbers greater then -8 but less then 8
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4 years ago

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For the function f(x)=-6X^2+3X +7 Evaluate f(-1)

Zigmanuir [339]

Answer:

$f( - 1) = - 2$

Step-by-step explanation:

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I hope I helped you^_^

5 0

3 years ago

Find the slope of the line through the given points (8,-3), (5,-3)

fredd [130]

To calculate the slope, you can use the formula
$\frac{{y}^{2} - {y}^{1}}{{x}^{2} - {x}^{1} }$
In this case,
$\frac{( - 3) - ( - 3)}{8 - 5}$
Your slope is 0/3, which does not make sense so there should be something incorrect about your points.

7 0

3 years ago