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kkurt [141]
2 years ago
10

Use the formula S A = 6s2 , where S A is the surface and s is the edge length of the cube , to solve his problem.

Mathematics
1 answer:
Gennadij [26K]2 years ago
4 0
To find the surface area of the cube using the formula, you would substitute in 2 1/2 for the length of the side.

SA = 6 x 2.5 x 2.5
SA = 37.5 ft.²

You are finding the area of one face (2.5 x 2.5) and multiplying it by six because there are six groups of this.
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Henry's baseball practice starts at 2:00 pm. It lasts 1 hour and 45 minutes. What time does he get out of baseball practice? Wri
Andrew [12]

Answer:

3:45

Step-by-step explanation:

because if you add 2 to 1 it is 3 and that is 3pm and it says 2:00 and the 00 are the minutes minutes so you can add those in and it will be 45 so 3:45

5 0
2 years ago
A student graphed f(x)=x and g(x)= f(x)-8 on the same coordinate grid. Which statement best describes how the graph of f and g a
luda_lava [24]

Answer:

The correct option is D

The graph of f is shifted 8 units down to create the graph of g.

Explanation:

Given f(x) = x

If the graph of this function is shifted 8 units down, we have

x - 8

This is the function f(x) - 8

Since g(x) = f(x) - 8, we conclude that the graph of f is shifted 8 units down to create the graph of g.

7 0
1 year ago
The rate at which the temperature is dropping is 6t 5t2 degrees Celsius per hour t hours after sundown. How much had the tempera
Whitepunk [10]

Using a differential equation, it is found that the temperature dropped 72 degrees Celsius between sundown and 3 hours after sundown.

<h3>What is the differential equation that describes the temperature in t hours after sundown?</h3>

The rate at which the temperature is dropping is 6t + 5t^2 degrees Celsius per hour t hours after sundown, hence the <em>differential equation</em> is:

\frac{dT}{dt} = 6t + 5t^2

Applying <em>separation of variables</em>, we find the solution as follows:

\frac{dT}{dt} = 6t + 5t^2

dT = (6t + 5t^2) dt

\int dT = \int (6t + 5t^2) dt

T(t) = \frac{5t^3}{3} + 3t^2 + T(0)

In which T(0) is the temperature at sundown.

In 3 hours, the change will be of:

C = T(3) - T(0) = \frac{5t^3}{3} + 3t^2|_{t = 3}

Hence:

\frac{5(3)^3}{3} + 3(3)^2 = 45 + 27 = 72

The temperature dropped 72 degrees Celsius between sundown and 3 hours after sundown.

You can learn more about differential equations at brainly.com/question/24348029

5 0
2 years ago
My teacher used 3/4 a foot of tape on my poster. She used half a foot of tape on my friends poster. How much more tape did she u
ella [17]

Answer: 1/4

Step-by-step explanation:

3/4-1/2=1/4

5 0
3 years ago
GURRY FOR BRAINLEIST PLS HURRY
pashok25 [27]

Answer:

C= 10.6

Step-by-step explanation:

AB^2=AC^2+CB^2

C^2=7^2+8^2

C^2= 113

√113=10.630

5 0
3 years ago
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