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Gala2k [10]
3 years ago
14

Which of the following has no solution?

Mathematics
1 answer:
zheka24 [161]3 years ago
5 0

{x | x < 0} and {x | x > 0}  NO SOLUTION   <em>(look at the picture)</em>

<em>There is no number that is both positive and negative.</em>

{x | x ≤ 0} and {x | x ≥ 0} SOLUTION: the number 0

{x | x ≤ 0} or {x | x ≥ 0}  SOLUTION: all real numbers


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Combine like terms to find the equivalent expression to 6(5/8u+1)-6(-7/4u-5)
IgorLugansk [536]

Answer:

B

Step-by-step explanation:

Distribute 6 to 5/8u and 1 and you get 15/4u + 6. Distribute -6 to -7/4u and -5 and you get 21/2u and 30. The equation will be 15/4u + 6 + 21/2u + 30 and then combine like terms to get 57/4u + 36.

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3 years ago
Estimate the product of 97×422
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Answer:40934

Step-by-step explanation:

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Car rental company A charges $45 a day to rent a certain car. Car rental B charges $30 a day plus $0.20 per mile to rent a simil
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3 years ago
Blood pressure values are often reported to the nearest 5 mmHg (100, 105, 110, etc.). The actual blood pressure values for nine
Paladinen [302]

Answer:

a) 117.4

b) 117.9

c) Option A)  When there is rounding or grouping, the median can be highly sensitive to small change

Step-by-step explanation:

We are given the following data set in the question:

108.6, 117.4, 128.4, 120.0, 103.7, 112.0, 98.3, 121.5, 123.2

Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}

n = 9

a) Median of the reported blood pressure values

Sorted Values: 98.3, 103.7, 108.6, 112.0, 117.4, 120.0, 121.5, 123.2, 128.4

Median =

\dfrac{9 + 1}{2}^{th}\text{ term} = 5^{th}\text{ term} = 117.4

b) New median of the reported values

Data: 108.6, 117.9, 128.4, 120.0, 103.7, 112.0, 98.3, 121.5, 123.2

Sorted Values: 98.3, 103.7, 108.6, 112.0, 117.9, 120.0, 121.5, 123.2, 128.4

New Median =

\dfrac{9 + 1}{2}^{th}\text{ term} = 5^{th}\text{ term} = 117.9

c) Since median is a position based descriptive statistics, a small change in values can bring a change in the median value as the order of the data may change.

Option A)  When there is rounding or grouping, the median can be highly sensitive to small change

7 0
3 years ago
What must be true for lines a and b to be parallel lines? Check all that apply.
Dima020 [189]

Answer:

Option (1), (2) , (7) and (8) is correct.

Step-by-step explanation:

Given: a║b  and d and c be transversal , We have to find the value of x and measure of angle 1 and 2.

Since, a║b  and d be a transversal  then ,

∠BXZ = ∠AZP = 58° ( corresponding angles )

Thus, m∠2 = 58°

∠BYC = ∠XYZ = (4X-10)° (vertically opposite angles)

Since, a║b  and c be a transversal  then,

  ∠XYZ = ∠QZU = (4X-10)°  (Corresponding angles)

Thus, m∠1 =  (4X-10)°

Also, Since, 'a' is a straight line.

Sum of angles on a straight line is 180°.

⇒ ∠PZA + ∠PZQ + ∠QZU = 180°

⇒ 58° +(3X-1)°+(4X-10)° = 180°

⇒ 58° + 7x - 11 = 180°

⇒ 47° + 7x  = 180°

⇒  7x  = 180°- 47°

⇒  7x  = 133°

⇒  x  = 19°

Put x = 19 in (3X-1)° and (4X-10)° , we get

(3X-1)° = (3(19)-1)° = 56°

(4X-10)° = (4(19)-10)°= 66

Thus, (3X-1)° ≠ (4X-10)°

Thus, option (1), (2) , (7) and (8) is correct.


5 0
3 years ago
Read 2 more answers
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