The best explanation for this is 2.When looking atypBT and ASPM, some individuals counted as parental are actually double recombinant
The sum of the two intervening distances is larger than the distance between the outside genes DBT and ASPM (less than 33 map units). Why? because not all of the recombination events (double crossovers) are taken into account by the calculated distance between DBT and ASPM.
Thus, the map distance would have been greater if there were more double recombinants. Again, the map distance would decrease if the number of parents was higher. The map distance is lower here than anticipated. This indicates that the number of parents is higher than it ought to be.
Therefore, the best choice is 2.
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(complete question)
You are measuring recombination between three genes: DBT, MEN2 and ASPM. The recombination fraction between the DBT and MFN2 is 15% and between MFN2 and ASPM is 18%: However, the recombination fraction between DBT and ASPM is slightly smaller than, but close to, 33%. What is the best explanation for this?
- One of these genes may be on different chromosomes than the other two but this fact is masked because of double recombinants
- When looking atypBT and ASPM, some individuals counted as parental are actually double recombinant
- When looking at DBT and ASPM, some individuals counted as double recombinants are actually parental
- DBT and ASPM actually assort independently
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Initiation: Replication begins at a specific location called as OriC, at which some initiator protein bind and cause unwinding
Elongation: New DNA stand grows, one base pair at a time.
Termination: The two new double helices replace the older ones and the last primer strand is removed, followed by proofreading.
