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3 years ago

Answer please I need real bad help and I live alone

Mathematics

2 answers:

tatyana61 [14]3 years ago

8 0

Answer:

C is the answer

Step-by-step explanation:

VARVARA [1.3K]3 years ago

6 0

Answer:

The answer is C

Step-by-step explanation:

First you look to the X axis and then the Y, so you found the -3 at the X axis and you look to the Y axis. Then you try and find the 4, so the answer is C. Remember to always look at the X axis first.

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A customer opens a checking account and a savings account at a bank. They will deposit a maximum of $600, some in the checking a

zhenek [66]

Answer:

Not enough info for a valid answer.

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

If you select one card at random from a standard deck of 52 cards, what is the probability that the card is a five AND a club?

horsena [70]

Probability is expressed as

number of favorable outcomes/number of total outcomes

The number of cards in a deck is 52(total outcomes)

Recall, there is only 1 five of clubs in a deck of cards(favorable outcomes)

Thus, the probability that the card is a five AND a club is 1/52

4 0

1 year ago

If the ratio of corresponding segments is 2:3, then the ratios of the areas and volumes are

kobusy [5.1K]

Answer:

4:9

Step-by-step explanation:

Area is squaring and Volume is cubing

So it'd be 2^2:3^3, or 4:9

I hope this helped and have a good rest of your day!

6 0

3 years ago

If F is the midpoint for EG then, x = ?

guapka [62]

I hope this helps you

EF=FG

6x-4=5x+7

x=11

3 0

3 years ago

Read 2 more answers

In a certain lottery, you must select 5 numbers (in any order) out of 26 correctly to win. a. How many ways can 5 numbers be

Step2247 [10]

Answer:

a. 7893600

$b.\ \dfrac{1}{26}$

Step-by-step explanation:

Given that there are 26 numbers out of which 5 numbers are to be chosen.

Here repetition is not allowed.

For each of the 5 cases, the total number of possibilities will keep on decreasing by 1.

1st case, number of possibilities = 26

2nd case, number of possibilities = 25

3rd case, number of possibilities = 24

4th case, number of possibilities = 23

5th case, number of possibilities = 22

a. Total number of possibilities = 26 $\times$ 25 $\times$ 24 $\times$ 23 $\times$ 22 = <em>7893600</em>

b. Probability of winning by choosing one number:

Formula for probability of an event E can be observed as: $P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

Number of favorable cases = 1

Total number of cases = 26

So, required probability:

$P(E) = \dfrac{1}{26}$

So, the answers are:

a. 7893600

$b.\ \dfrac{1}{26}$

5 0

3 years ago