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3 years ago

13

Make b the subject.

1 answer:

sp2606 [1]3 years ago

6 0

First, square both sides. This will cancel out the radical.
$a^2 = b \add 6$
(a^2 = b + 6)
Then subtract 6 from both sides
b = a^2 - 6

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1. Solve for the x and y intercepts:

aleksandrvk [35]

To find the x-intercept, you simply make y equal to 0 and solve the equation for x. To find the y-intercept, you make x equal to 0 and solve for y. So, for number 1, the answer is D because when you set it to y equals 0, you get x=3 and when you set it to x equals 0, you get 4.
Number 2 we would do the same thing and get D as well.
Hope this helps!

4 0

3 years ago

The ratio of boys to girls in history class is 4to5 how many girls are in class if there are 12 boys in the class

DENIUS [597]

The answer is 15 girls

6 0

3 years ago

Read 2 more answers

Pls help me not fail

nignag [31]

Answer:

D

Step-by-step explanation:

Using the Cosine rule to find AC

AC² = BC² + AB² - (2 × BC × AB × cosB )

= 18² + 12² - ( 2 × 18 × 12 × cos75° )

= 324 + 144 - 432cos75°

= 468 - 111.8

= 356.2 ( take the square root of both sides )

AC = $\sqrt{356.2}$ ≈ 18.9

-----------------------------------------

Using the Sine rule to find ∠ A

$\frac{18}{sinA}$ = $\frac{18.9}{sin75}$ ( cross- multiply )

18.9 sinA = 18 sin75° ( divide both sides by 18.9 )

sinA = $\frac{18sin75}{18.9}$ , then

∠ A = $sin^{-1}$ ( $\frac{18sin75}{18.9}$ ) ≈ 66.9°

4 0

3 years ago

Simplify the expression 4 + 23−|−4| <br> A.16 B.4 C.8 D.12

Artyom0805 [142]

Answer: =23

Step-by-step explanation:

$4+23-\left|-4\right|$

$=4+23-4$

$=23$

7 0

2 years ago

In the game of roulette, a player can place a $4 bet on the number 29 and have a 1/38 probability of winning. If the metal bal

creativ13 [48]

Answer:

The expected value of the game to the player is -$0.2105 and the expected loss if played the game 1000 times is -$210.5.

Step-by-step explanation:

Consider the provided information.

It is given that if ball lands on 29 players will get $140 otherwise casino will takes $4.

The probability of winning is 1/38. So, the probability of loss is 37/38.

Now, find the expected value of the game to the player as shown:

$E(x)=(140)\times \frac{1}{38}+(-4)\times \frac{37}{38}$

$E(x)=\frac{140-148}{38}$

$E(x)=\frac{-8}{38}=-$0.2105$

Hence, the expected value of the game to the player is -$0.2105.

Now find the expect to loss if played the game 1000 times.

1000×(-$0.2105)=-$210.5

Therefore, the expected loss if played the game 1000 times is -$210.5.

5 0

3 years ago