The answer is 8069 insects
P(t) = A * e^(r*t)
P(t) - <span>the insect population at the end of t weeks.
A - the initial number of insects
r - the growth rate
t - number of weeks
P(t) = ?
A = 20
r = 50% = 0.5
t = 12 weeks
P(t) = </span>20 * e^(0.5*12)
P(t) = 20 *
P(t) = 20 * e^(0.5*12)
P(t) = 20 * 403.43
P(t) ≈ 8069 insects
Four million, seven hundred thirty thousand.
A slope of 1/2 means for every two units to the right we move up one.
We have to be careful here because the graphs don't always use the same scale for x and y.
The bottom left uses the same scale and does indeed go two units to the right for every unit up, so that one is the answer.
Yeah you are correct, also I need brainlest please
