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spin [16.1K]
3 years ago
6

What’s the answer ASAP will give brainlist

Mathematics
1 answer:
disa [49]3 years ago
7 0
It’s 1, looks like you got it lol
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Describe the sequence of basic rigid motions that shoews S1 = S2
telo118 [61]

Answer:

S1 is congruent to S2

Step-by-step explanation:

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2 years ago
At a point on the ground 46 feet from the foot of a tree, the angle of elevation of the top of the tree is 68 degrees. What is t
Mandarinka [93]

Answer:

114 ft

Step-by-step explanation:

Imagine or construct a right triangle with the 46 ft leg lying on the ground.  This is the "adjacent side" of the triangle; it lies immediately adjacent to the 68 degree angle.  The side opposite this angle is h, the height of the tree.

The tangent function includes angle, opp side and adj side:

tan 68 degrees = opp / adj = h / (46 ft), and so:

(46 ft)*tan (68 degrees) = opp = h

Then the height of the tree is h = (46 ft)(2.47) = 114 ft

6 0
3 years ago
The value of loga (30a)^3 is
postnew [5]
Part 1 of the solution.

8 0
3 years ago
The diameter of your bicycle wheel is 34 inches. How far will you move in one turn of your wheel? What is the distance covered i
irga5000 [103]
In one turn of the wheel, you will move the circumference of the wheel. To find the circumference, you just do π × diameter, so π × 34 = 106.8 inches. In 5 turns, you will just go 5 times the circumference, so you multiply by 5 to get 534.1 inches. I hope this helps!
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3 years ago
Define fn : [0,1] --> R by the
sasho [114]

Answer:

The sequence of functions \{x^{n}\}_{n\in \mathbb{N}} converges to the function

f(x)=\begin{cases}0&0\leq x.

Step-by-step explanation:

The limit \lim_{n\to \infty }c^{n} exists and converges to zero whenever \lvert c \rvert. But, if c=1 the sequence \{c^{n}\} is constant and all its terms are equal to 1, then converges to 1. Using this result, consider the sequence of functions \{f_{n}\} defined on the interval [0,1] by f_{n}(x)=x^{n}. Then, for all 0\leq x we have that \lim_{n\to \infty}x^{n}=0. Now, if x=1, then \lim_{n\to \infty }x^{n}=1. Therefore, the limit function of the sequence of functions is

f(x)=\begin{cases}0&0\leq x.

To show that the convergence is not uniform consider 0. For any n>1 choose x\in (0,1)  such that \varepsilon^{1/n}. Then

\varepsilon

This implies that the convergence is not uniform.

8 0
3 years ago
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