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FinnZ [79.3K]
4 years ago
10

Circle A is shown with a central angle marked 40 degrees and the radius marked 15 inches. Which of the following could be used t

o calculate the area of the sector in the circle shown above?
Mathematics
2 answers:
Virty [35]4 years ago
8 0

Alright, lets get started :

The area of sector is = 1/2 θ r^2 where θ is in radians

So lets first change our given angle θ ie 40 degree into radian.

For changing degree to radian, we multiply 40 * Pi/180 = 0.698 radians

Now lets plug the value in formula

Area = 1/2 θ r^2

Area = 1/2 * 0.698 * 15^2

Area = 78.54 square inches : Answer

Hope that will help :)

Veseljchak [2.6K]4 years ago
5 0

In degrees, the area of a sector is

A=\frac{\theta}{360}*\pi   r^2

Since our central angle is 40 degrees, and our radius is 15, our formula will look like this:

A=\frac{40}{360}*(15)^2\pi and

A=\frac{40}{360}*225\pi. Not sure how far you need to go with this as far as reducing or solving, but that's the formula. The actual area is \frac{225\pi}{9}, or in decimal form 78.54 rounded

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Which of the following is the solution of One-fourth x + 5 = 7? x = 2 x = 6 x = 8 x = 12
salantis [7]
Changes made to your input should not affect the solution:

(1): "x1" was replaced by "x^1". 3 more similar replacement(s).

Step by step solution :

Step 1 :

Equation at the end of step 1 :

x + ((((3•19x2) • x6) • x8) • x12)
Step 2 :

Step 3 :

Pulling out like terms :

3.1 Pull out like factors :

57x28 + x = x • (57x27 + 1)

Trying to factor as a Sum of Cubes :

3.2 Factoring: 57x27 + 1

Theory : A sum of two perfect cubes, a3 + b3 can be factored into :
(a+b) • (a2-ab+b2)
Proof : (a+b) • (a2-ab+b2) =
a3-a2b+ab2+ba2-b2a+b3 =
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Check : 57 is not a cube !!


Final result :

x • (57x27 + 1)

Processing ends successfully
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