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Andreyy89
3 years ago
13

ANSWER THIS QUICK QUESTION FOR 16 POINTS!

Mathematics
1 answer:
salantis [7]3 years ago
7 0

I believe it's C E.

They both look pretty equal and line up perfectly with E. Hope this helps!

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(b) What portion of the official U.S. poverty threshold (roughly $29,000 for a family of four) is met by the World Bank’s measur
otez555 [7]
World Bank's threshold for poverty is $1.25 per person per day. 
For a family of four this gives:
Daily income = (number of people) * threshold
Daily income = 4 * $1.25
Daily income = $5
For a year this is:
Yearly income = (daily income) *365
Yearly income = $5 *365
Yearly income = $1825

U.S. poverty threshold is set at $29000. Portion of threshold can be calculated as:
Portion\text{ }of\text{ }threshold= \frac{Poverty\text{ }threshold\text{ }(World\text{ }Bank)}{Poverty\text{ }threshold\text{ }(U.S.)} *100\% \\  \\ Portion\text{ }of\text{ }threshold= \frac{1825}{29000} *100\% \\  \\ Portion\text{ }of\text{ }threshold=6.29\%

The poverty threshold measured by World Bank is 6.29% of the U.S. poverty threshold.
5 0
3 years ago
M= -3 b= -1 slope intercept form ​
Aliun [14]

Answer:

y = -3x-1

Step-by-step explanation:

all u had to do was plug it into y = mx+b

5 0
3 years ago
PLS HELP ME ILL MARK BRAINIEST
skad [1K]

Answer:

Question 1- 288.48

Step-by-step explanation:

depending on how they round your answer the number might look different.

V= Bh which means (pi)r^2(h)

3.14 x 1.25^2 x 4.9

V=24.040625 ~ 24.04

12 x 24.04

=288.48

5 0
2 years ago
6.3 divided by 2.5 HELP ME PLZZZZZZZZZZZZZZZ
Vadim26 [7]

Answer:

6.3/2.5=2.52

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2
Montano1993 [528]

Answer:

\dfrac{m^3}{16p^2q^2}

Step-by-step explanation:

Given:

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}

1.

m^{-1}=\dfrac{1}{m}

2.

q^0=1

3.

2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}

4.

(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}

5.

m^{-1}=\dfrac{1}{m}

6.

2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}

7.

\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}

8.

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}

8 0
3 years ago
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