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3 years ago

Find the value of x in the isoscleles triangle sqrt45 and altitude 3

Mathematics

1 answer:

Alisiya [41]3 years ago

8 0

Answer:

$c.\hspace{3}x=12$

Step-by-step explanation:

Isosceles triangles are a type of triangles in which two of their sides have an identical length. It should be noted that the angles opposite the sides that are the same length are also the same. This means that these triangles not only have two equal sides, but also two equal angles.

You can solve this problem using different methods, I will use pythagorean theorem. First take a look at the picture I attached. As you can see:

$x=2a$

And we can find a easily using pythagorean theorem:

$(\sqrt{45} )^{2} =3^{2} +a^{2}$

Solving for a:

$a^{2} =(\sqrt{45} )^{2} -3^{2} \\\\a^{2} =45-9\\\\$

$a^{2} =36\\\\a=\sqrt{36} \\\\a=6$

Therefore:

$x=2a\\\\x=2(6)\\\\x=12$

You might be interested in

Which expressions are equivalent?

trapecia [35]

Only 3(a−b) and 3a−3b are equivalent

Further explanation:

We have to evaluate each expression to evaluate if the expressions are equivalent or not.

So,

$3(a-b)\\Distributing\ 3\ in\ bracket\\3.a-3.b\\=3a-3b$

As we can see that 3(a-b) results in 3a-3b so these are equivalent

$2a(2+b)\\Distributing\ 2a\\2a.2+2a.b\\=4a+2ab$

As we can see that 2a(2+b) doesn't result in 4ab so these are not equivalent

Hence,

Only 3(a−b) and 3a−3b are equivalent

Keywords: Equivalent expression, Polynomials

Learn more about polynomials at:

#LearnwithBrainly

3 0

3 years ago

Suppose the number of children in a household has a binomial distribution with parameters n=12n=12 and p=50p=50%. Find the proba

nadya68 [22]

Answer:

a) 20.95% probability of a household having 2 or 5 children.

b) 7.29% probability of a household having 3 or fewer children.

c) 19.37% probability of a household having 8 or more children.

d) 19.37% probability of a household having fewer than 5 children.

e) 92.71% probability of a household having more than 3 children.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem, we have that:

$n = 12, p = 0.5$

(a) 2 or 5 children

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{12,2}.(0.5)^{2}.(0.5)^{10} = 0.0161$

$P(X = 5) = C_{12,5}.(0.5)^{5}.(0.5)^{7} = 0.1934$

$p = P(X = 2) + P(X = 5) = 0.0161 + 0.1934 = 0.2095$

20.95% probability of a household having 2 or 5 children.

(b) 3 or fewer children

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{12,0}.(0.5)^{0}.(0.5)^{12} = 0.0002$

$P(X = 1) = C_{12,1}.(0.5)^{1}.(0.5)^{11} = 0.0029$

$P(X = 2) = C_{12,2}.(0.5)^{2}.(0.5)^{10} = 0.0161$

$P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.0537$

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0002 + 0.0029 + 0.0161 + 0.0537 = 0.0729$

7.29% probability of a household having 3 or fewer children.

(c) 8 or more children

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{12,8}.(0.5)^{8}.(0.5)^{4} = 0.1208$

$P(X = 9) = C_{12,9}.(0.5)^{9}.(0.5)^{3} = 0.0537$

$P(X = 10) = C_{12,10}.(0.5)^{10}.(0.5)^{2} = 0.0161$

$P(X = 11) = C_{12,11}.(0.5)^{11}.(0.5)^{1} = 0.0029$

$P(X = 12) = C_{12,12}.(0.5)^{12}.(0.5)^{0} = 0.0002$

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) = 0.1208 + 0.0537 + 0.0161 + 0.0029 + 0.0002 = 0.1937$

19.37% probability of a household having 8 or more children.

(d) fewer than 5 children

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{12,0}.(0.5)^{0}.(0.5)^{12} = 0.0002$

$P(X = 1) = C_{12,1}.(0.5)^{1}.(0.5)^{11} = 0.0029$

$P(X = 2) = C_{12,2}.(0.5)^{2}.(0.5)^{10} = 0.0161$

$P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.0537$

$P(X = 4) = C_{12,4}.(0.5)^{4}.(0.5)^{8} = 0.1208$

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0002 + 0.0029 + 0.0161 + 0.0537 + 0.1208 = 0.1937$

19.37% probability of a household having fewer than 5 children.

(e) more than 3 children

Either a household has 3 or fewer children, or it has more than 3. The sum of these probabilities is 100%.

From b)

7.29% probability of a household having 3 or fewer children.

p + 7.29 = 100

p = 92.71

92.71% probability of a household having more than 3 children.

5 0

3 years ago

After 5 years, mike's account earned $1200 in interest. If the interest rate (in decimal form) is 0.06, how much did mike initia

Maksim231197 [3]

20000 your welcome

need help ask me

8 0

3 years ago

Read 2 more answers

Can someone help me with this problem

Romashka [77]

Step-by-step explanation:

Find the slope of JK by the formula :y2-y1/(x2-x1) whose value is 4/5

similarly, calculate the slope of GH it's value is also 4/5

Find slope of GK now by same formula y2-y1/( x2-x1 ).the value will be -5/3

Similarly calculate slope of HJ and you will get its value to be -5/3

since parallel lines have equal slopes JK and GH are parallel and GK and HJ are parallel. Since opposite sides are parallel GHJk is parallelogram

5 0

2 years ago

What is the slope? 18,4.5/20,5

jarptica [38.1K]

Answer:

m = 0.5 / 2 = 0.25

Step-by-step explanation:

7 0

2 years ago

Find the value of x in the isoscleles triangle sqrt45 and altitude 3​

Find the value of x in the isoscleles triangle sqrt45 and altitude 3