We have to find the area first
12 x 18=216 square feet
we do 216* $ 1.39= $ 300.24
Answer:
Step-by-step explanation:
To find : Acceleration in first 15 min . Distance between two cities Average speed of journey
Solution:
Each horizontal block is 1/8 hr = 7.5 min
Each vertical block is 10 km/hr
Time Velocity km/hr
0 Min ( 0 hr) 0
15 Min (1/4 hr) 50
45 Min (3/4 hr) 50
60 MIn ( 1 hr) 100
90 Min ( 3/2 hr) 100
120 Min ( 2hr) 0
Acceleration in first 15 min (1/4 hr) = (50 - 0)/(1/4 - 0) = 50/(1/4)
= 200 km/h²
Distance between two cities
= (1/2)(0 + 50)(1/4 - 0) + 50 * (3/4 - 1/4) + (1/2)(50 + 100)(1 - 3/4) + 100 * (3/2 - 1) + (1/2)(100 + 0)(2 - 3/2)
= 25/4 + 25 + 75/4 + 50 + 25
= 125
Distance between two cities = 125 km
Average Speed of journey = 125/2 = 62.5 km/hr
Acceleration in first 15 min = 200 km/h²
Distance between two cities = 125 km
Average Speed of journey = 62.5 km/hr
Hope this helps..
Answer:
277.1 feets
Step-by-step explanation:
Drop height = 120 feets
Ball bounces 2/5 of previous height
Height after 1st bounce :
120 * 2/5 = 48 feets
Return distance = 48 feets
Height after second bounce :
48 * (2/5) = 19.2 feets
Return distance = 19.2 feets
Height after 3rd bounce :
19.2 * (2/5) = 7.68 feets
Return distance = 7.68 feets
Height after 4th bounce :
7.68 * (2/5) = 3.072 feets
Return distance = 3.072 feets
Height after 5th bounce :
3.072 * (2/5) = 1.2288 feets
(120 + (2*48) + (2*19.2) + (2*7.68) + (2*3.072) + 1.2288) = 277.1328
= 277.1 feets