It’s real my easy you can use a calculator or an online converter. Or division
(111001)₂ = (1 × 2⁵) + (1 × 2⁴) + (1 × 2³) + (0 × 2²) + (0 × 2¹) + (1 × 2⁰) = (57)₁₀
(1100000)₂ = (1 × 2⁶) + (1 × 2⁵) + (0 × 2⁴) + (0 × 2³) + (0 × 2²) + (0 × 2¹) + (0 × 2⁰) = (96)₁₀
(1010101)₂ = (1 × 2⁶) + (0 × 2⁵) + (1 × 2⁴) + (0 × 2³) + (1 × 2²) + (0 × 2¹) + (1 × 2⁰) = (85)₁₀
(1001000)₂ = (1 × 2⁶) + (0 × 2⁵) + (0 × 2⁴) + (1 × 2³) + (0 × 2²) + (0 × 2¹) + (0 × 2⁰) = (72)₁₀
Answer:
The project file can be managed by making its multiple version due to the following reasons.
1. We can create multiple copies or version of the project to avoid any unfortunate circumstance such as Project file can be corrupted or can be deleted. In that case we can use the other version of that project file.
2. When we are working on some project, we are modifying the code or program to achieve our desired results. In this process we may forgot the changes that we have made while modification. If we does not obtain our desired results while modification that can lead to losing the original file. To reduce this type of risk we create multiple versions of project File.
3. We also create version of our project files on some internet drives as a backup. In case our computer has lost or operating system has been corrupted. A version of our project file is available on Internet drives such as Google drive or Drop box.
The atomic number for Neon is 10.
I do not see the info for the second part of the question
Answer:
retupmoc
Explanation:
1.) Anwser will be retupmoc
because
public static String mysteryString(String s){
if(s.length() == 1){
return s;
}
else{
return s.substring(s.length() -1) + mysteryString(s.substring(0, s.length()-1));
}
}
In this program input is "computer" . So the function mysteryString(String s) it does
return s.substring(s.length() -1) + mysteryString(s.substring(0, s.length()-1));
so when it enters the first time ??s.substring(s.length() -1) and it will be give you 'r' then it calls the function recursively by reducing the string length by one . So next time it calls the mysteryString function with string "compute" and next time it calls return s.substring(s.length()-1)? + mysteryString(s.substring(0,s.length-1)) so this time it gives "e" and calls the function again recursively . It keeps on doing till it matched the base case.
so it returns "retupmoc".
A design was operating at a maximum clock frequency of f and the clock had no jitter. if the clock started to have jitter of t secs, what will be the new frequency?
