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horsena [70]
3 years ago
15

Which relationship is possible when two tables share the same primary key? one-to-one one-to-many many-to-one many-to-many

Computers and Technology
2 answers:
Finger [1]3 years ago
8 0
Many-to-one relationships is possible when two tables share the same primary key it is because one entity contains values that refer to another entity that has unique values. It often enforced by primary key relationships, and the relationships typically are between fact and dimension tables and between levels in a hierarchy.
disa [49]3 years ago
3 0

for plato many-to-one is not the answer

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The return value is a one-dimensional array that contains two elements. These two elements indicate the rows and column indices
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Answer:

In Java:

import java.util.Scanner;  

import java.util.Arrays;  

public class Main  {  

public static void main(String args[])  {  

Scanner input = new Scanner(System.in);

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    for(int j =0;j<col;j++){

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    }     }

 

int[] maxarray = findmax(Array2D,row,col);

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System.out.println("Column: "+(maxarray[1]+1));

}  

public static int[] findmax(int[][] Array2D,int row, int col)   {  

int max = Array2D[0][0];

int []maxitem = new int [2];

for(int i =0;i<row;i++){

    for(int j =0;j<col;j++){

        if(Array2D[i][j] > max){  

            maxitem[0] = i;

            maxitem[1] = j; } }    }

 

return maxitem;  

}  

}

Explanation:

The next two lines import the scanner and array libraries

<em>import java.util.Scanner;   </em>

<em>import java.util.Arrays;   </em>

The class of the program

<em>public class Main  {  </em>

The main method begins here

<em>public static void main(String args[])  {  </em>

The scanner function is called in the program

<em>Scanner input = new Scanner(System.in);</em>

This declares the array row and column

int row, col;

This next instructions prompt the user for rows and get the row input  

System.out.print("Rows: ");    row = input.nextInt();

This next instructions prompt the user for columns and get the column input  

System.out.print("Cols: ");     col = input.nextInt();  

This declares the 2D array

int[][] Array2D = new int[row][col];

This prompts the user for array elements

System.out.print("Enter array elements: ");

The following iteration populates the 2D array

<em> for(int i =0;i<row;i++){    </em>

<em>     for(int j =0;j<col;j++){ </em>

<em>         Array2D[i][j] = input.nextInt();   </em>

<em>     }     } </em>

This calls the findmax function. The returned array of the function is saved in maxarray  

int[] maxarray = findmax(Array2D,row,col);

This prints the row position

System.out.println("Row: "+(maxarray[0]+1));

This prints the column position

System.out.println("Column: "+(maxarray[1]+1));

The main method ends here

}  

The findmax function begins here

public static int[] findmax(int[][] Array2D,int row, int col)   {  

This initializes the maximum to the first element of the array

int max = Array2D[0][0];

This declares maxitem. The array gets the position of the maximum element

int []maxitem = new int [2];

The following iteration gets the position of the maximum element

<em>for(int i =0;i<row;i++){ </em>

<em>     for(int j =0;j<col;j++){ </em>

<em>         if(Array2D[i][j] > max){  </em>

<em>             maxitem[0] = i; </em><em>-- The row position is saved in index 0</em><em> </em>

<em>             maxitem[1] = j;  </em><em>-- The column position is saved in index 1</em><em>} }    } </em>

This returns the 1 d array

return maxitem;  

}  

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