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horsena [70]
3 years ago
15

Which relationship is possible when two tables share the same primary key? one-to-one one-to-many many-to-one many-to-many

Computers and Technology
2 answers:
Finger [1]3 years ago
8 0
Many-to-one relationships is possible when two tables share the same primary key it is because one entity contains values that refer to another entity that has unique values. It often enforced by primary key relationships, and the relationships typically are between fact and dimension tables and between levels in a hierarchy.
disa [49]3 years ago
3 0

for plato many-to-one is not the answer

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4 years ago
Color ___ indicates that one color is dominating a picture.
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4 years ago
Given two integers as user inputs that represent the number of drinks to buy and the number of bottles to restock, create a Vend
Zanzabum

Answer:

import java.util.Scanner;

class Main {

 public static void main (String args[])

 {

   Scanner input = new Scanner(System.in);

   VendingMachine machine = new VendingMachine(20);

   System.out.print("Enter nr to purchase: ");

   int nrPurchased = input.nextInt();

   System.out.print("Enter nr to re-stock: ");

   int nrRestock = input.nextInt();

   machine.Transaction(nrPurchased, nrRestock);

   input.close();

 }

}

class VendingMachine {

 private int inventory;

 public VendingMachine(int initialInventory) {

   inventory = initialInventory;

 }

 public void Transaction(int nrToBuy, int nrToRestock) {

   inventory += nrToRestock - nrToBuy;

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7 0
3 years ago
What's wrong with my program? Here is my code , if the user wants a 3rd card dealt they, have to select yes and the total will b
Mashcka [7]

Your issue is on line 19 in your if statement. In python, if you have more than one condition in an if statement, you have to explicitly mention it after the or.

Your if statement is

if again == "Y" or "y":

However, this will always return true because the second statement simply asks "y".

To correct this, simply change the if statement to:

if again == "Y" or again == "y":

This will correct your code.

Another thing to consider is to always convert a userinput (whenever possible) to one version, this can be accomplished in your code by converting "again" into one version by using the .lower function.

again = input("Would you like to draw a 3rd card? Y or N? ")

again = again.lower()

Hope this helps!

4 0
2 years ago
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