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3 years ago

Which relationship is possible when two tables share the same primary key? one-to-one one-to-many many-to-one many-to-many

2 answers:

8 0

Many-to-one relationships is possible when two tables share the same primary key it is because one entity contains values that refer to another entity that has unique values. It often enforced by primary key relationships, and the relationships typically are between fact and dimension tables and between levels in a hierarchy.

disa [49]3 years ago

3 0

for plato many-to-one is not the answer

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Please debug the below code in Java please.

lisabon 2012 [21]

Answer:

Check the explanation

Explanation:

//Bugs are highlighted in bold text

class Invoice

Declarations

private num invoiceNumber

private string customer

private num balanceDue

private num tax

public void setInvoiceNUMBER(num number)

Declarations

num LOW_NUM = 1000

num HIGH_NUM = 9999

if number > HIGH_NUM then

invoiceNumber = 0

else

if number < LOW_NUM then

invoiceNumber = 0

else

invoiceNumber = num

endif

return

public void setCustomer(string cust)

customer = cust

return

public void setBalanceDue(num balance)

//Bug balanceDue is Invoice class varible

//but it is assigned to balance .it gives error

balance = balanceDue

setTax()

return

private void setTax()

Declarations

//Bug TAX_RATE is declared as string

//but assigned a double value

string TAX_RATE = 0.07

tax = tax * TAX_RATE

return

public void displayInvoice()

output "Invoice #", invoiceNumber

output "Customer: ", customer

output "Due: ", balanceDue

output "Tax: ", taxDue

//Bug

//Invoice class has no variable called balance .it should be balanceDue

output "Total ", balance + taxDue

return

endClass

start

Declarations

Invoice inv1

Invoice inv2

Invoice inv3

//Warning

//it gives warning object taken but not initilaized

Invoice inv4

inv1.setInvoiceNumber(1244)

inv1.setCustomer("Brown")

inv1.setBalanceDue(1000.00)

inv1.displayInvoice()

inv2.setInvoiceNumber(77777)

inv2.setCustomer("Jenkins")

inv2.setBalanceDue(2000.00)

inv2.displayInvoice()

inv3.setInvoiceNumber(888)

inv3.setCustomer("Russell")

inv3.setBalanceDue(3000.00)

//Bug

//setTax method of Invioce doesnot take any arguments

inv3.setTax(210.00)

inv3.displayInvoice()

stop

//Here is the complete program in c++

//Run the program using Microsoft visual studio 2010 vc++

#include<iostream>

#include<iomanip>

#include<string>

using namespace std;

class Invoice

{

//class varibales

private:

int invoiceNumber;

string customer;

double balanceDue;

double tax;

//class methods

public:

void setCustomer(string cus);

void displayInvoice();

void setBalanceDue(double balance);

void setInvoiceNUMBER(int number);

void setTax();

};

void Invoice::displayInvoice()

{

cout<< setw(10)<<"Invoice #"<<setw(5)<<invoiceNumber<<endl;

cout<<setw(10)<<"Customer: "<<setw(5)<<customer<<endl;

cout<<setw(10)<<"Due: "<<setw(5)<<balanceDue<<endl;

cout<<setw(10)<<"Tax: "<<setw(5)<<tax<<endl;

//Bug

//Invoice class has no variable called balance .it should be balanceDue

cout<< "Total "<< balanceDue + tax<<endl;

}

void Invoice::setCustomer(string cust)

{

customer = cust;

}

void Invoice::setInvoiceNUMBER(int number)

{

const int LOW_NUM = 1000;

const int HIGH_NUM = 9999;

if( number > HIGH_NUM )

invoiceNumber = 0;

else

if (number < LOW_NUM )

invoiceNumber = 0;

else

invoiceNumber = number;

}

void Invoice::setBalanceDue(double balance)

{

balanceDue = balance;

}

void Invoice::setTax()

{

double TAX_RATE = 0.07;

tax = balanceDue * TAX_RATE;

}

int main()

{

Invoice inv1;

Invoice inv2;

Invoice inv3;

inv1.setInvoiceNUMBER(1244);

inv1.setCustomer("Brown");

inv1.setBalanceDue(1000.00);

inv1.setTax();

inv1.displayInvoice();

inv2.setInvoiceNUMBER(77777);

inv2.setCustomer("Jenkins");

inv2.setBalanceDue(2000.00);

inv2.setTax();

inv2.displayInvoice();

inv3.setInvoiceNUMBER(888);

inv3.setCustomer("Russell");

inv3.setBalanceDue(3000.00);

inv3.setTax();

inv3.displayInvoice();

system("pause");

return 0;

}

Kindly check the output image below.

5 0

3 years ago

Please check my answer! (Java)

Nat2105 [25]

9 is the correct answer. 4*2=8 loops are executed, moving the count from 1 to 9.

8 0

3 years ago

What is the wave speed of a wave that has a frequency of 100 Hz and a wavelength of 0.30m?

swat32

Answer:

The speed is

=

30

m

s

−

1

Explanation:

The speed of a wave is given by

speed

(

m

s

−

1

)

=

frequency(Hz)

×

wavelength (m)

The frequency is

f

=

100

H

z

The wavelength is

λ

=

0.3

m

The speed is

v

=

λ

f

=

0.3

⋅

100

=

30

m

s

−

1

6 0

3 years ago

Matthew is working to select an authentication method for his company that will support REST as well as many web-based and mobil

vitfil [10]

Answer:

C) OpenID Connect

Explanation:

The best option is OpenID Connect because is based in OAuth, and supports multiple web based and mobile clients, and supports REST.

With OAuth, we cannot make any user authentication just provide a token to access data.

RADIUS is a networking protocol, and Shibboleth is a single sign-on log-in system for computer networks and the Internet, both not support REST.

6 0

2 years ago

Create a flowchart that assigns a counselor to a student.

Nataly [62]

Please Help! Unit 6: Lesson 1 - Coding Activity 2
Instructions: Hemachandra numbers (more commonly known as Fibonacci numbers) are found by starting with two numbers then finding the next number by adding the previous two numbers together. The most common starting numbers are 0 and 1 giving the numbers 0, 1, 1, 2, 3, 5...
The main method from this class contains code which is intended to fill an array of length 10 with these Hemachandra numbers, then print the value of the number in the array at the index entered by the user. For example if the user inputs 3 then the program should output 2, while if the user inputs 6 then the program should output 8. Debug this code so it works as intended.

The Code Given:

import java.util.Scanner;

public class U6_L1_Activity_Two{
public static void main(String[] args){
int[h] = new int[10];
0 = h[0];
1 = h[1];
h[2] = h[0] + h[1];
h[3] = h[1] + h[2];
h[4] = h[2] + h[3];
h[5] = h[3] + h[4];
h[6] = h[4] + h[5];
h[7] = h[5] + h[6];
h[8] = h[6] + h[7]
h[9] = h[7] + h[8];
h[10] = h[8] + h[9];
Scanner scan = new Scanner(System.in);
int i = scan.nextInt();
if (i >= 0 && i < 10)
System.out.println(h(i));
}
}

4 0

2 years ago

Read 2 more answers