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Pepsi [2]
3 years ago
5

Any one can help me 6x___=9 Help...

Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
7 0

____ is equal to 1.5. You can solve this by dividing both sides of the equation by 6 (doing it on the side with the missing number gets rid of it so it just leaves our mystery number or variable) and 9/6 is 1.5.

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-15=2t-11 does any one know it please
Murljashka [212]

Add 11 to both sides:

-4=-2t

divide 2 by both sides

2=t

Hope it helps! Comment if you have any questions!

5 0
3 years ago
Read 2 more answers
A soup can will have a radius of 4 cm and a
DENIUS [597]

Answer:

<h3>            It's about 365 cm²</h3>

Step-by-step explanation:

2×πr² + 2πr×h =

= 2×π×4² + 2π×4×10.5 =

= 32π + 84π =

= 116π ≈

≈ 364.42 cm²

5 0
3 years ago
What is the slope of the line?
jeyben [28]

Answer:

C, -2

Step-by-step explanation:

-4x + 7 = 2y - 3

-4x + 10 = 2y

-2y = 4x - 10

y = -2x + 5

5 0
3 years ago
Find the length of the segment QS.(Enter the just the value, without any units.)
motikmotik

Answer:

QS = 15

Step-by-step explanation:

Thales

QS/QT = RS/PT

QS = QT·RS/PT

= 20×12/16

= 240/16

= 15

3 0
4 years ago
Read 2 more answers
There are approximately 3,000 bass in a lake. The population grows at a rate of 2% per year. Round answers to the nearest tenth.
Tamiku [17]

Answer:

years 1–4: 62.4 bass per year

years 5–8: 67.6 bass per year

Step-by-step explanation:

If the population in year n is ...

 p(n) = 3000·1.02^n

then the average rate of change from year 1 to year 4 is ...

 (p(4) -p(1))/(4 -1) = 3000(1.02^4 -1.02^1)/3 = 1020·(1.02^3 -1) ≈ 62.4

The average rate of change for years 1–4 is 62.4 bass per year.

For years 5–8, the rate of change is similarly computed:

 (p(8) -p(5))/(8 -5) = 3000(1.02^8 -1.02^5)/3 = 1000·1.02^5·(1.02^3 -1) ≈ 67.6

The average rate of change for years 5–8 is 67.6 bass per year.

5 0
3 years ago
Read 2 more answers
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