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Genrish500 [490]
3 years ago
5

Can please answer these 3 questions

Mathematics
1 answer:
kupik [55]3 years ago
6 0
So it would be 32 lol if
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Please help and dont get it wrong! thank you =)))
Nataly [62]

Answer:

tanong mo sa may mga nakaka alam niyan para walang mali, thanks

5 0
3 years ago
7. Select True or False for each statement.
rewona [7]
A. True
B. False
C. False
D. False
E. True

B. Quadrant II contains ordered pairs of the form (negative number, positive number)
C. (-6,0) is located on the x-axis
D. The origin is not located on any of the quadrant. It’s in the center
8 0
3 years ago
A coin is tossed 88 times. what is the probability of getting all tails? express your answer as a simplified fraction or a decim
dmitriy555 [2]

|\Omega|=2^{88}=309485009821345068724781056\\ |A|=1\\\\ P(A)=\dfrac{1}{309485009821345068724781056}

4 0
3 years ago
Rida and elisa are each paid by the hour. rida worked 5 1\2. hours and earned 77. elisa worked 3 3\4 HOURS AND EARNED 60. WHOSE
skad [1K]
Rida:
5 1/2 :77
5.5 : 77
Divide both sides by 5.5 to get $/hour:
1:14

Elisa:
3 3/4:60
3.75:60
Divide both sides by 3.75 to get $/hour:
1:16

16 is bigger than 14 so Elisa earns more.

Hope this helps :)

5 0
3 years ago
A plane takes off from an airport and flies at a speed of 400km/h on a course of 120° for 2 hours. the plane then changes its co
butalik [34]

Answer:

Distance from the airport = 894.43 km

Step-by-step explanation:

Displacement and Velocity

The velocity of an object assumed as constant in time can be computed as

\displaystyle \vec{v}=\frac{\vec{x}}{t}

Where \vec x is the displacement. Both the velocity and displacement are vectors. The displacement can be computed from the above relation as

\displaystyle \vec{x}=\vec{v}.t

The plane goes at 400 Km/h on a course of 120° for 2 hours. We can compute the components of the velocity as

\displaystyle \vec{v_1}=

\displaystyle \vec{v_1}=\ km/h

The displacement of the plane in 2 hours is

\displaystyle \vec{x_1}=\vec{v_1}.t_1=.(2)

\displaystyle \vec{x_1}=km

Now the plane keeps the same speed but now its course is 210° for 1 hour. The components of the velocity are

\displaystyle \vec{v_2}=

\displaystyle \vec{v_2}=km/h

The displacement in 1 hour is

\displaystyle \vec{x_2}=\vec{v_2}.t_2=.(1)

\displaystyle \vec{x_2}=km

The total displacement is the vector sum of both

\displaystyle \vec{x_t}=\vec{x_1}+\vec{x_2}=+

\displaystyle \vec{x_t}=km

\displaystyle \vec{x_t}=

The distance from the airport is the module of the displacement:

\displaystyle |\vec{x_t}|=\sqrt{(-746.41)^2+492.82^2}

\displaystyle |\vec{x_t}|=894.43\ km

8 0
4 years ago
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