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2 years ago

Pls help answer it's due in 10 minutes

Mathematics

1 answer:

djverab [1.8K]2 years ago

4 0

1/2y-1 because you reduce the numbers

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A group of 12 company employees wants to buy a $100 gift card for the boss's birthday. Six employees each contributed $7.75. How

stepladder [879]

Note: 6 employees means half of the employees contributed $7.75 each.

6 x $7.75 = $46.50.

To find how much money remains to be collected, subtract $46.50 from $100.

So, $100 - $46.50 = $53.50 is the answer.

5 0

3 years ago

I need help with these because recently we have been learning this and I don't get any of this.

Aleksandr-060686 [28]

It is upside down, can't see it properly!

5 0

3 years ago

Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete

icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 17 means that $N = 17$

4 are carrying nucleas weapons, which means that $k = 4$

9 are destroyed, which means that $n = 9$

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294$

$P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588$

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0

2 years ago

I need help with this ASAPP

torisob [31]

Answer:

Step-by-step explanation:

you can see the factors in the green section of the venn diagram. Of all the factors, 6 is the largest.

Hope this helps!

7 0

3 years ago

Read 2 more answers

Which of these steps in constructing an inscribed square using technology

quester [9]

<span>Mark the point of intersection between Circle eight in line A.B.</span>

4 0

3 years ago

Pls help answer it's due in 10 minutes​

Pls help answer it's due in 10 minutes