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svlad2 [7]
3 years ago
14

Solve the inequation 3p-15 < p-2

Mathematics
1 answer:
irina [24]3 years ago
6 0
P < 6.5 is the answer
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The area (A of a circle with a radius of ris given by the formula A = 772 and its diameter (d) is given by d = 27. Arrange the e
lions [1.4K]

Answer:

A = πr² ← r is the radius and r = \frac{1}{2} d ← d is the diameter

Hence

π (\frac{1}{2} d)² = A, that is

\frac{d^2\pi }{4} = A ( multiply both sides by 4 )

d²π = 4A ( divide both sides by π )

d² = \frac{4A}{\pi } ( take the square root of both sides )

d = \sqrt{\frac{4A}{\pi } }

4 0
3 years ago
12x - 16 = 68<br> Solve for x
cricket20 [7]

Answer:

x = 7

Step-by-step explanation:

12x - 16 = 68

Add 16 to each side

12x - 16+16 = 68+16

12x =84

Divide by 12

12x/12 = 84/12

x = 7

6 0
3 years ago
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1 ⅕ - ⅓ = ? <br><br> Please I need help--
Sunny_sXe [5.5K]
1 1/5 - 1/3
6/5-1/3
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13/15 is your answer.
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3 years ago
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Find the remainder when 3x^3+ 6x-1 is divided by x-3​
Sauron [17]

Answer:

93

Step-by-step explanation:

by remainder theorem p(3) is the remainder

and therefore it is 93

3 0
3 years ago
The x3 was supposed to be an exponent not 3x
mote1985 [20]

Answer:

The value of x is 2\sqrt[3]{2}

Step-by-step explanation:

We are given 2+x^3=18

We need to solve for x

First we subtract 2 both sides

x^3=18-2=16

Taking cube roots both sides to isolate x

x=\sqrt[3]{16}

Simplify the radical

x=2\sqrt[3]{2}

Thus, The value of x is 2\sqrt[3]{2}

8 0
3 years ago
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