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xeze [42]
3 years ago
10

Help i need to find what the surface area of the piramid is excluding the base

Mathematics
1 answer:
Alex17521 [72]3 years ago
6 0
SA = 1/2 Pl + B ; P(perimeter of base) , l(slant height) , B(area of base)
= 1/2 (4)(8) (6) + 8^2
= 1/2 (32)(6) + 64
= 96 + 64
= 160

letter D :)))
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A factory makes 12 bikes in 3 hours. If it keeps making bikes at the same rate, how many bikes will it have made in 8 hours? (HI
Vilka [71]

Answer:32

Step-by-step explanation: 4 bikes every hour so multiply 4 times 8 which is 32

4 0
3 years ago
I don’t know how to solve this
Romashka-Z-Leto [24]

Answer:

see explanation

Step-by-step explanation:

The perimeter is the length of all the sides in the figure.

The arc of the semi- circle is included in this.

length of arc = \frac{1}{2}πd ← d is the diameter

here d = 8, hence

arc = \frac{1}{2}π × 8 = 4π ← exact length

Perimeter = 10 + 8 + 10 + 4π ≈ 40.57 in ( nearest hundredth )

3 0
3 years ago
Which is NOT true?<br> 9 + 4 = 17 - 4<br> 8 + 7 = 14 + 3<br> 11 = 19 - 8<br> 5 + 8 = 20 - 7
Fynjy0 [20]
8+7 = 14+3 is the false answer
4 0
3 years ago
Mir evaluated 5x - (x + 3)2 for x = 2, as shown. Describe Amir's mistake and find the correct answer. 5(2) - (2 + 3)2 = 10 + (-5
sleet_krkn [62]

Answer:correct answer =0

Step-by-step explanation:

Step 1

5x - (x + 3)2

Putting the coefficient of x =2 in the equaton we have

5(2) - (2 + 3)2

Solving out

5(2) - (5)2

= 10- 10

=0

Step 2

Amir's mistake was in the multiplication  and wrong use of the negative sign of the bolded below

5(2) - (2 + 3)2 = 10 + (-5)2 = 10 + 25 = 35

-(5)2 cannot give 25 instead 10, so him getting a 25 and wrong use of the negative and positive made his answer wrong.

The right answer as calculated in step 1 = 0

4 0
3 years ago
Read 2 more answers
Consider the initial value problem 2ty′=4y, y(2)=−8. 2ty′=4y, y(2)=−8. find the value of the constant cc and the exponent rr so
Softa [21]
2ty'=4y
Replacing y'=dy/dt in the equation:
2t(dy/dt)=4y
Grouping terms:
dy/y=4dt/(2t)
dy/y=2dt/t
Integrating both sides:
ln(y)=2ln(t)+ln(c), where c is a constant
Using property logarithm:  b ln(a) = ln(a^b), with b=2 and a=t
ln(y)=ln(t^2)+ln(c)
Using property of logarithm: ln(a)+ln(b) = ln(ab), with a=t^2 and b=c
ln(y)=ln(ct^2)
Then:
y=ct^2
Using the initial condition: y(2)=-8
t=2→y=-8→c(2)^2=-8→c(4)=-8
Solving for c:
c=-8/4
c=-2

Then the solution is y=-2t^2
Comparing with the solution: y=ct^r
c=-2, r=2

Answer: T<span>he value of the constant c is -2 (c=-2) and the exponent r is 2 (r=2)</span>
 
5 0
3 years ago
Read 2 more answers
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