Question

Find the gretest number which devded by 181 and 236 leave a remainder of 5 in each case​

Answer 1

Answer:

The greatest number is 11

Step-by-step explanation:

Given

Dividends: 181 and 236

Remainder: 5

Required

Determine a divisor that satisfies the above condition

Let the required divisor be represented with x.

Since a remainder of 5 is expected, then x can divide (181 - 5) and (236 - 5) without remainders.

So, we have:

$181 - 5 = 176$

$236 - 5 = 231$

Next, we calculate the GCF of 176 and 231

$176 = 2 * 2 * 2 * 2 * 11$

$231 = 3 * 7 * 11$

The greatest common factor, GCT is:

$GCF = 11$

Hence, the required divisor is 11