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3 years ago

11

Colinda has just purchased her first home for $125,000. She put down a 20 percent down payment of $25,000 and took out a 5 perce

nt mortgage for the rest. Her mortgage payment is $477 per month. How much of her first monthly mortgage payment is amortization?
A) $60.33

B) $243.67

C) $325.33

D) $143.67

1 answer:

german3 years ago

3 0

The amount of amortization for the first month is $60.33.

For complete calculations, see question 9835011
or see attached image.

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In college Dak Prescott had a record of 5 to 2, which represented his

kenny6666 [7]

Answer:

y = 3 x = 5

Step-by-step explanation:

If x is the game number, and y is the amount of touchdown passes for that specific game number, then (5,3) represents the idea that the quarter back threw y = 3 touchdown passes for game number x = 5

So the answer is choice D. This is the only ordered pair that comes from the given table. Something like (2,4) isn't true because the quarterback threw 1 touchdown pass (not 4) in game two.

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How, do you divide big numbers.

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Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Find n. Perimeter = 86 in.

FromTheMoon [43]

Let the length of rectangle be L and the width of rectangle be W.
Since length exceeds the width by 25 inches, length will be
L = W + 25

Now the perimeter, P, is given by
P = 2(L + W)
Substituting L = W + 25 in the above equation,
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P = 2(2W + 25)
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3 years ago

The first three terms of a sequence are given. Round to the nearest thousandth (if necessary).

kramer

Given:

The sequence is:

$16,80,400,...$

To find:

The 6th term of the given sequence.

Solution:

We have,

$16,80,400,...$

Here, the first term is:

$a=16$

The ratio between consecutive terms are:

$\dfrac{80}{16}=5$

$\dfrac{400}{80}=5$

The given sequence has a common ratio 5. So, the given sequence is a geometric sequence.

The nth term of a geometric sequence is:

$a_n=a(r)^{n-1}$

Where, a is the first term and r is the common ratio.

Substitute $a=16,r=5,n=6$ to get the 6th term.

$a_6=16(5)^{6-1}$

$a_6=16(5)^{5}$

$a_6=16(3125)$

$a_6=50000$

Therefore, the 6th term of the given sequence is 50000.

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3 years ago

Assuming that the equation defines x and y implicitly as differentiable functions xequalsf(t), yequalsg(t), find the slope of

Doss [256]

Answer:

$\dfrac{dx}{dt} = -8,\dfrac{dy}{dt} = 1/8\\$

Hence, the slope , $\dfrac{dy}{dx} = \dfrac{-1}{64}$

Step-by-step explanation:

We need to find the slope, i.e. $\dfrac{dy}{dx}$ .

and all the functions are in terms of $t$ .

So this looks like a job for the 'chain rule', we can write:

$\dfrac{dy}{dx} = \dfrac{dy}{dt} .\dfrac{dt}{dx} -Eq(A)$

Given the functions

$x = f(t)\\y = g(t)\\$

and

$x^3 +4t^2 = 37 -Eq(B)\\2y^3 - 2t^2 = 110 - Eq(C)$

we can differentiate them both w.r.t to $t$

first we'll derivate Eq(B) to find dx/dt

$x^3 +4t^2 = 37\\3x^2\frac{dx}{dt} + 8t = 0\\\dfrac{dx}{dt} = \dfrac{-8t}{3x^2}\\$

we can also rearrange Eq(B) to find x in terms of t , $x = (37 - 4t^2)^{1/3}$ . This is done so that $\frac{dx}{dt}$ is only in terms of t.

$\dfrac{dx}{dt} = \dfrac{-8t}{3(37 - 4t^2)^{2/3}}\\$

we can find the value of this derivative using t = 3, and plug that value in Eq(A).

$\dfrac{dx}{dt} = \dfrac{-8t}{3(37 - 4t^2)^{2/3}}\\\dfrac{dx}{dt} = \dfrac{-8(3)}{3(37 - 4(3)^2)^{2/3}}\\\dfrac{dx}{dt} = -8$

now let's differentiate Eq(C) to find dy/dt

$2y^3 - 2t^2 = 110\\6y^2\frac{dy}{dt} -4t = 0\\\dfrac{dy}{dt} = \dfrac{4t}{6y^2}$

rearrange Eq(C), to find y in terms of t, that is $y = \left(\dfrac{110 + 2t^2}{2}\right)^{1/3}$ . This is done so that we can replace y in $\frac{dy}{dt}$ to make only in terms of t

$\dfrac{dy}{dt} = \dfrac{4t}{6y^2}\\\dfrac{dy}{dt}=\dfrac{4t}{6\left(\dfrac{110 + 2t^2}{2}\right)^{2/3}}\\$

we can find the value of this derivative using t = 3, and plug that value in Eq(A).

$\dfrac{dy}{dt} = \dfrac{4(3)}{6\left(\dfrac{110 + 2(3)^2}{2}\right)^{2/3}}\\\dfrac{dy}{dt} = \dfrac{1}{8}$

Finally we can plug all of our values in Eq(A)

but remember when plugging in the values that $\frac{dy}{dt}$ is being multiplied with $\frac{dt}{dx}$ and NOT $\frac{dx}{dt}$ , so we have to use the reciprocal!

$\dfrac{dy}{dx} = \dfrac{dy}{dt} .\dfrac{dt}{dx}\\\dfrac{dy}{dx} = \dfrac{1}{8}.\dfrac{1}{-8} \\\dfrac{dy}{dx} = \dfrac{-1}{64}$

our slope is equal to $\dfrac{-1}{64}$

7 0

3 years ago