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andreyandreev [35.5K]
2 years ago
12

In college Dak Prescott had a record of 5 to 2, which represented his

Mathematics
1 answer:
kenny6666 [7]2 years ago
5 0

Answer:

y = 3  x = 5

Step-by-step explanation:

If x is the game number, and y is the amount of touchdown passes for that specific game number, then (5,3) represents the idea that the quarter back threw y = 3 touchdown passes for game number x = 5

So the answer is choice D. This is the only ordered pair that comes from the given table. Something like (2,4) isn't true because the quarterback threw 1 touchdown pass (not 4) in game two.

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Subtract.<br> 5<br><br> 27x<br> - <br><br> 75x
Nadya [2.5K]
I think the answer is x=0 the equation is not set up clearly
5 0
3 years ago
Find the slope of the line that passes through (6, 68) and (54,-7)​
soldi70 [24.7K]

Answer:

-25/16

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-7-68)/(54-6)

m=-75/48

m=-25/16

7 0
2 years ago
Read 2 more answers
An 80% confidence interval is found to be (0.52, 0.58) what is the sample proportion?
Mazyrski [523]

Answer: 55

Step-by-step explanation:

ape

3 0
3 years ago
The human body has a normal temperature of 98.6°F. Doctors will get worried if a sick patient has a temperature that varies from
makvit [3.9K]

Answer:

|T- 98.6| \geq 3

And in order to solve this we have two possibilities:

Solution 1

T -98.6 \leq -3

And solving for T we got:

T \leq 98.6- 3

T\leq 95.6

Solution 2

And the other options would be:

T -98.6 \geq 3

T \geq 101.6

Step-by-step explanation:

For this case we can define the variable os interest T as the real temperature and we know that if we are 3 F more than the value of 98.6 we will be unhealthy so we can set up the following equation:

|T- 98.6| \geq 3

And in order to solve this we have two possibilities:

Solution 1

T -98.6 \leq -3

And solving for T we got:

T \leq 98.6- 3

T\leq 95.6

Solution 2

And the other options would be:

T -98.6 \geq 3

T \geq 101.6

6 0
3 years ago
Assume that the weight loss for the first month of a diet program varies between 6 pounds and 14 pounds, and is spread evenly ov
Llana [10]

Hello!

For this uniform distribution, the shape of the density function is a line. We can begin by identifying key elements of the distribution:

Range: 6 to 14 pounds

Formula of density function:

y = 1/Range

1 - (14 - 6) = 1/8 = 0.125

f(x) = 0.125

1)

P(x = 7)

A uniform distribution is a continuous distribution, so the probability of x being an EXACT value is approximately 0.

<u>This is the same as if we took the following integral. (Finding the area under a curve with the same start and end point)</u>
\int\limits^a_a {f(x)} \, dx  = 0

Therefore, P(x = 7) = 0.

2)
We can think of this as finding the area of a rectangle.

The width would be the difference between 8.25 pounds and 12 pounds:
W = 12 - 8.25 = 3.75

The height would be the function (y = .125), or:
h = .125

Using the equation for the area of a rectangle: (A = h * w)

A = 3.75 * .125 = 0.469

Thus, P(8.25 < x < 12) = 0.469

3)
To find the probability GREATER than 10.50 pounds, we can subtract this value from the max value for the width:
W = 14 - 10.50 = 3.50

The height is the same as above:
h = .125

Solve for the area:
A = 3.50 * .125 = 0.4375

P(x > 10.5) = 0.4375

5 0
2 years ago
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