All categories

4 years ago

A horizontal line has what type of slope?

Mathematics

2 answers:

OverLord2011 [107]4 years ago

8 0

Answer:

The slope of any horizontal line is zero, 0. All points that lie on the line have a negative coordinate.

malfutka [58]4 years ago

6 0

Answer:

Horizontal Lines A horizontal line is a line whose equation is of the form =, where is a real number. All points that lie on the line have a -coordinate of . The slope of any horizontal line is zero, 0.

Step-by-step explanation:

You might be interested in

What is the slope of the line through (-1, 4) and (1, -2)? <br>A. 1/3<br> B. 3 <br>C. -3 <br>D. 3

vazorg [7]

Answer:

Step-by-step explanation:

Using the slope formula:

(-2-4)/1-(-1)

-6/2

-3

The slope is -3!

Hope this helped!

6 0

3 years ago

Triangle ABC has vertices at (-4,0) , (-1, 6) and (3,-1) perimeter of triangle ABC, rounded to the nearest tenth ?

makvit [3.9K]

Answer:

The perimeter of triangle ABC is $P=21.8\ units$

Step-by-step explanation:

The perimeter of triangle ABC is equal to

$P=AB+BC+AC$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$A(-4,0),B(-1, 6),C(3,-1)$

step 1

Find the distance AB

$A(-4,0),B(-1, 6)$

substitute in the formula

$d_A_B=\sqrt{(6-0)^{2}+(-1+4)^{2}}$

$d_A_B=\sqrt{(6)^{2}+(3)^{2}}$

$d_A_B=\sqrt{45}\ units$

step 2

Find the distance BC

$B(-1, 6),C(3,-1)$

substitute in the formula

$d_B_C=\sqrt{(-1-6)^{2}+(3+1)^{2}}$

$d_B_C=\sqrt{(-7)^{2}+(4)^{2}}$

$d_B_C=\sqrt{65}\ units$

step 3

Find the distance AC

$A(-4,0),C(3,-1)$

substitute in the formula

$d_A_C=\sqrt{(-1-0)^{2}+(3+4)^{2}}$

$d_A_C=\sqrt{(-1)^{2}+(7)^{2}}$

$d_A_C=\sqrt{50}\ units$

step 4

Find the perimeter

$P=AB+BC+AC$

substitute the values

$P=\sqrt{45}+\sqrt{65}+\sqrt{50}=21.8\ units$

8 0

3 years ago

Find (f^-1)'(7) without finding the inverse function where f(x) = 5 – 2x^3.

faltersainse [42]

Step-by-step explanation:

the derivative of an inverse function is

1/f'(f^-1(x))

f'(x) = -6x²

f^-1(7) is solving the original function equation for x under the knowledge that y = 7

7 = 5 - 2x³

2 = -2x³

-1 = x³

x = -1

f'(-1) = -6×(-1)² = -6×1 = -6

so,

(f^-1)'(7) = -1/6

5 0

3 years ago

A store sells 3 T-shirts for $27.42. What is the unit cost per T-shirt?

natima [27]

Answer:

$9.14

Step-by-step explanation:

27.42 divided by 3 = $9.14 per shirt

4 0

4 years ago

Read 2 more answers

Find the common ratio of the geometric sequence.

Kay [80]

Answer:

The common ratio is $\frac{1}{x^4}$

Step-by-step explanation:

Geometric sequence:A geometric sequence is a sequence in which the ratio of any term to the preceding term of that term is always constant.

Common ratio: The ratio of any term to the preceding term of that term.

The $n^{th}$ term of a geometric sequence is represented by $a_n=ar^{n-1}$ .

The $1^{st}$ term of the sequence = a.

The sum of first n term is

$S_n=\frac{a(1-r^n)}{1-r}$

The common ratio = r.

Given geometric sequence,

$\frac{1}{x^{10}}$ , $\frac{1}{x^{14}}$ , $\frac{1}{x^{18}}$ , $\frac{1}{x^{22}}$ ........

The common ratio is

$=\frac{\textrm{second term}}{\textrm{first term}}$

$=\frac{\frac{1}{x^{14}}}{\frac{1}{x^{10}}}$

$=\frac{x^{10}}{x^{14}}$

$=\frac{1}{x^4}$

6 0

4 years ago