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wel
3 years ago
6

Find (f^-1)'(7) without finding the inverse function where f(x) = 5 – 2x^3.

Mathematics
1 answer:
faltersainse [42]3 years ago
5 0

Step-by-step explanation:

the derivative of an inverse function is

1/f'(f^-1(x))

f'(x) = -6x²

f^-1(7) is solving the original function equation for x under the knowledge that y = 7

7 = 5 - 2x³

2 = -2x³

-1 = x³

=>

x = -1

f'(-1) = -6×(-1)² = -6×1 = -6

so,

(f^-1)'(7) = -1/6

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4 years ago
If one factor of x2+2x-24 is (x+6), what is the other factor
lyudmila [28]

Answer:

<h2>(x-4)</h2>

Step-by-step explanation:

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= x^2-4x+6x-24

Step 2: Factorize out common terms

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Factorize out (x-4)

(x-4)(x+6)

x^{2} +2x-24\\Write+2x -as-a-difference\\x^{2} -4x+6x-24\\Factor out common terms\\x(x-4)+6(x-4)\\Factor out (x+4)\\(x-4)(x+6)

3 0
3 years ago
Find the value of B - A if the graph of Ax + By = 3 passes through the point (-7, 2), and is parallel to the graph of x + 3y = -
geniusboy [140]

Answer:

The found values are:

A = 1/3

B = -8/3

Step-by-step explanation:

We know that general equation is given by:

y = mx + c

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x + 3y = -5

y =  -(1/3)x - 1/3(5)

Slop of the equation is -(1/3). As parallel line have same slope, substitute it in the first equation:

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B(2) = -7/3 - 3

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B = -16/6

B = -8/3

5 0
3 years ago
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