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hram777 [196]
3 years ago
13

The data represents the results for a test for a certain disease. Assume one individual from the group is randomly selected. Fin

d the probability of getting someone who tests negative, given that he or she had the disease.The probability is approximately? ( Round to three decimal (places as needed.)Positive Yes. No 137 8Negative 16 139
Mathematics
1 answer:
Zepler [3.9K]3 years ago
5 0

Answer: 8/145

Step-by-step explanation: Rewriting the table

Positive and Negative stand for the result of the test

Yes and No stand for having the disease

          Positive       |      Negative     | Total

<u>Yes </u><u>  |     137           |             8           |   145</u>

<u>No  </u><u>  |       16           |            139        |    155</u>

<u>Total</u><u> |     153           |            147        |   300</u>

<u />

probability of getting someone who tests negative, given that he or she had the disease.

P(Negative | Yes) = <u>P(Negative ∩ Yes)</u> = <u> 8 </u>

                                        P(Yes)              145        

<u />

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-144r = -12rk find the value
OLga [1]

k = 12

cancel out the r on both sides

then divide -144 by -12.

you get 12.

5 0
3 years ago
Need help!! I can't figure this out
Sidana [21]

9514 1404 393

Answer:

  12. $1,035,057.23

  13. $988,881.23

  14. $7,762.93

  15. $8,686.16

  16. $967,647.66

Step-by-step explanation:

The annuity and amortization formulas are used for problems like this.

  sum of monthly payments = P((1 +r/12)^(12t) -1)/(r/12)

  monthly amount available = P(r/12)/(1 -(1 +r/12)^(-12t))

__

12. The sum of monthly payments of 74, accumulated at 9% compounded monthly for 52 years is ...

  A = ($74)((1 +.09/12)^(12·52) -1)/(.09/12) = $1,035,057.23

__

13. The total of payments is ...

  $74×12×52 = $46,176

So, the interest earned is ...

  $1,035,057.23 -46,176 = $988,881.23

__

14. The amount available in perpetuity is the monthly interest on this account balance.

  $1,035,057.23 × .09/12 = $7,762.93

__

15. The monthly amount available for 25 years is found from the amortization formula:

  A = $1,035,057.23(.09/12)/(1 -(1 +.09/12)^(-12·25)) = $8686.16

__

16. The amortization formula is used for this, too.

  8066 = P(.094/12)/(1 -(1 +.094/12)^(-12·30)) = 0.00833568P

  P = $8066/0.00833568 = $967,647.66

7 0
2 years ago
Please help!!! asap
MakcuM [25]

Answer: y = x^2 + 6x+ 9 = 0. (X+3)^2= 0 when x=3. This has one root.

X^2-2x -24 = 0 a= 1 b=-1 and c= -24 x = {-(-1) +/- sqrt((-1)^2 -4 x 1 x (-24)}/2

X = [1 +/- sqrt(97)]/2

Step-by-step explanation:

6 0
3 years ago
A raffle offers one $8000.00 prize, one $4000.00 prize, and five $1600.00 prizes. There are 5000 tickets sold at $5 each. Find t
Harman [31]

Answer:

The expectation is  E(1 )= -\$ 1

Step-by-step explanation:

From the question we are told that  

     The first offer is  x_1 =  \$ 8000

     The second offer is  x_2 =  \$ 4000

      The third offer is  \$ 1600

      The number of tickets is  n  =  5000

      The  price of each ticket is  p= \$ 5

Generally expectation is mathematically represented as

             E(x)=\sum  x *  P(X = x )

     P(X =  x_1  ) =  \frac{1}{5000}    given that they just offer one

    P(X =  x_1  ) = 0.0002    

 Now  

     P(X =  x_2  ) =  \frac{1}{5000}    given that they just offer one

     P(X =  x_2  ) = 0.0002    

 Now  

      P(X =  x_3  ) =  \frac{5}{5000}    given that they offer five

       P(X =  x_3  ) = 0.001

Hence the  expectation is evaluated as

       E(x)=8000 *  0.0002 + 4000 *  0.0002 + 1600 * 0.001

      E(x)=\$ 4

Now given that the price for a ticket is  \$ 5

The actual expectation when price of ticket has been removed is

      E(1 )= 4- 5

      E(1 )= -\$ 1

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2 years ago
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dexar [7]

Answer:

Angle 2 is 36 degrees

Step-by-step explanation:

73 - 37 = 36

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