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2 years ago

11

8 pleaseeeee help meeeee!

2 answers:

Dafna1 [17]2 years ago

7 0

Answer: what's the question

Step-by-step explanation: I cant see it

laiz [17]2 years ago

6 0

Answer:

Step-by-step explanation:

you sis it the wrong qwas

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Cuanto es 12 + 1? Porfavor es para mi tarea de matemáticas.

Nastasia [14]

Answer:

13

is your answer

Step-by-step explanation:

6 0

2 years ago

G (x)=x-3 and h(x)= square root of x, find(g o h) (25)

nevsk [136]

H(25) = sqrt25 = 5

g(5) = 5 - 3 = 2

answer is 2

7 0

2 years ago

Find the vectors T, N, and B at the given point. r(t) = < t^2, 2/3t^3, t >, (1, 2/3 ,1)

maxonik [38]

Answer with Step-by-step explanation:

We are given that

$r(t)=< t^2,\frac{2}{3}t^3,t >$

We have to find T,N and B at the given point t > (1, $2/3$ ,1)

$r'(t)=$

$\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1$

$T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}$

Now, substitute t=1

$T(1)=\frac{}{2+1}=\frac{1}{3}$

$T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}$

$T'(1)=-\frac{4}{9}+\frac{1}{3}$

$T'(1)=\frac{1}{9}=$

$\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}$

$N(1)=\frac{T'(1)}{\mid T'(1)\mid}$

$N(1)=\frac{}{\frac{2}{3}}=$

$N(1)=$

$B(1)=T(1)\times N(1)$

$B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}$

$B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})$

$B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k$

$B(1)=\frac{1}{3}$

5 0

2 years ago

Use the long division method to find the result when 12x^3+25x^2+4x-112x

slavikrds [6]

Answer:

(4x + 3) • (x + 2) • (3x - 2)

Thats finding the root polynomials hope it helps a bit

7 0

2 years ago

Can you answer this Algebra question please?<br> (Just A, thank you).

Eduardwww [97]

$d_f=d_i+v_0t+\dfrac{1}{2}at^2 \\d_f-d_i-\dfrac{1}{2}at^2=v_0t \\v_0=\boxed{\dfrac{d_f+d_i-\frac{1}{2}at^2}{t}} \\$

Hope this helps.

8 0

2 years ago

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