Answer
a) y | p(y)
25 | 0.8
100 | 0.15
300 | 0.05
E(y) = ∑ y . p(y)
E(y) = 25 × 0.8 + 100 × 0.15 + 300 × 0.05
E(y) = 50
average class size equal to E(y) = 50
b) y | p(y)
25 | 
100 | 
300 | 
E(y) = ∑ y . p(y)
E(y) = 25 × 0.4 + 100 × 0.3 + 300 × 0.3
E(y) = 130
average class size equal to E(y) = 130
c) Average Student in the class in a school = 50
Average student at the school has student = 130
Answer:
112.5
Step-by-step explanation:
24x=2700
=> x= 2700/24
= 112.5
Therefore, x= 112.5
Using the Pythagorean theorem a^2 +b^2 = c^2, where a and b are the sides of a triangle and c is the hypotenuse.
BA and AC are sides and BC is the hypotenuse.
we have 23^2 + b^2 = 45^2
529 + b^2 = 2025
b^2 = 2025 - 529
b^2 = 1496
b = sqrt(1496)
b = 38.68 = 38.7
The length of AC = 38.7
Step-by-step explanation:
(x × 5) +6=41
5x + 6=41
5x =41-6
5x=35
x=(35/5)
x=7