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Tanzania [10]
3 years ago
7

Need help please.I forgot this.

Mathematics
1 answer:
Sonbull [250]3 years ago
8 0
The associative property lets you move the parentheses.

6. (-20×50)×-29 = -1000×-29 = 29,000

7. (5×10)×18 = 50×18 = 900

8. 400 + (60 + 98) = 400 +158 = 558

9. 3×(20×5) = 3×100 = 300

10. (18 + 9) +91 = 27 +91 = 118
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Solve x/2 + y/3 = 1 for x
denis23 [38]

Answer:

x = - \frac{2y}{3} + 2

Step-by-step explanation:

Solve for x by simplifying both sides of the equation , isolating the variable.

Hope this helped you, Also please let me know if anything is unclear or wrong!

4 0
3 years ago
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Would anyone know this answer please
inna [77]
Money order would be the answer! Hope this helps you.
7 0
2 years ago
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See question in attached photo.<br>Answer question 4b and 5c​
sdas [7]

9514 1404 393

Answer:

  4b: 8.6 m/s²; 1.3×10^5 N; 2.1×10^4 N decrease

  5c: -1.6×10^12 J; -1.6×10^12 J

Step-by-step explanation:

<h3>4b</h3>

i) The acceleration due to gravity is inversely proportional to the square of the distance between the objects. The distance to the shuttle is ...

  1 + (5×10^5)/(6.4×10^5) = 69/64 . . . times the radius of the earth

Then the acceleration due to gravity at the height of the space shuttle is about ...

  (10 m/s²)(64/69)² ≈ 8.6 m/s²

__

ii) The weight of the space shuttle at that height is about ...

  F = ma = (15000 kg)(8.6 m/s²) ≈ 1.3×10^5 N

__

iii) The loss of weight will be ...

  ΔF = m(a1 -a0) = (15000 kg)(10 m/s² -8.6 m/s²)

  = 1.5×10^4×1.4 N = 2.1×10^4 N

____

<h3>5c</h3>

i) The gravitational potential energy is given by ...

  U = -GMm/r

where M and m are the mass of the earth and the rocket, respectively.

  U = -(6.67×10^-11)(6.0×10^24)(2.5×10^4)/(6.4×10^6) ≈ -1.6×10^12 J

__

ii) At a height of 3×10^4 m, the denominator in the above expression changes from 6.4×10^6 to 6.43×10^6. This changes the gravitational potential energy by a factor of 6.4/6.43 to -1.6×10^12 J

(Note: we're carrying only 2 significant figures in the result in accordance with the rules for precision in such calculations. The change is noticeable at the level of the 4th significant figure, less than 1/2%.)

4 0
2 years ago
(2x^2+4x+3) - (4x^2 -2x-3)
ankoles [38]

Answer:

x^{2}+6x+6 is your answer

7 0
2 years ago
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If a procedure meets all of the conditions of a binomial distribution except the number of trials is not​ fixed, then the geomet
natima [27]

Answer:

Given p = 0.07 as the probability that someone is a universal donor

In case of Geometric Distribution, Probability of  getting the first success on nth trial is given by

P (X=n) = p (1-p) ^ {n-1}

where p is the probability of success on any one trial and (1-p) shows the probability of failure.

So the probability of the first subject to be a universal blood donor will be the seventh person is

P (X=7) = 0.07 (1-0.07) ^ {7-1} = 0.07 (0.93) ^ 6 = 0.07*0.647 = 0.0453

So the final probability is 0.0453

3 0
3 years ago
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