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3 years ago

.How much force is needed to accelerate a truck with a mass of 2,000 kg, at a rate of 3 m/s²?

2 answers:

ozzi3 years ago

7 0

6000N

reason: according to Newton’s second law of motion, Force = Mass x Acceleration
using this, multiply 2000 by 3 to get 6000

RSB [31]3 years ago

4 0

2,000 kg at a rate of 3 miles per second to the second square

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Find the difference. (9/4x + 6)-(-5/4x-24)

Svetlanka [38]

Answer:

9x/4 + 30 + 5x/4

Step-by-step explanation:

$9x/4 +30 +5x/5$

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3 years ago

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4 years ago

What are the opposites of 7, -3.5, 2.25, and 9 1/3

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-7, 3.5, -2.25, -9 1/3

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3 years ago

To make the sum or difference of 3/4+1/3

rusak2 [61]

Answer:

13/12 or 1 1/12

Step-by-step explanation:

First, I like to line up the fractions like this:

3/4

1/3

You can't add them yet because they have different denominators, so we have to get them to the same denominator first. What is a number 3 and 4 can be multiplied by? Let's use 12. So, we want both of their denominators to be 12. How do we do that? 4 times what equals 12? 3. However, whatever you multiply the denominator by, you have to do to the numerator as well. Here is what we have:

3/4 x 3

1/3

3x3 equals 9, so your first fraction is 9/12. Then, do the second fraction. 3 times what equals 12? 4. So, multiply the numerator, 1, by 4 to get 4. So, your second fraction is 4/12. Now, you have to add them together, 9+4 = 13. The denominator stays the same. So, your sum is 13/12. If you want to, you can also simplify it to a mixed number into 1 1/12.

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3 years ago

Need help regarding radioactive decay type of question

Alik [6]

By applying the radioactive simple decay model, we find that the initial quantity of the radioactive isotope is equal to approximately 5.63 grams.

<h3>How to determine the initial mass of a radioactive isotope</h3>

Mass of radioactive isotopes (m (t)), in grams, decay exponentially in time according to the following model:

$m(t) = m_{o}\cdot e^{-t/\tau}$ (1)

Where:

$m_{o}$ - Initial mass, in grams
t - Time, in years
τ - Time constant, in years

The time constant can be found in terms of half-life:

τ = t'/㏑ 2

If we know that t' = 24100 yr, t = 1000 yr and m(t) = 5.4 g, then the initial mass of the radioactive isotope is:

τ = 24100 yr/㏑ 2

τ ≈ 34768.95 yr

$5.4 = m_{o}\cdot e^{-1000/24100}$

$m_{o} = 5.629\,g$

By applying the radioactive simple decay model, we find that the initial quantity of the radioactive isotope is equal to approximately 5.63 grams.

To learn more on radioactive decay: brainly.com/question/1770619

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2 years ago