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nalin [4]
3 years ago
9

.How much force is needed to accelerate a truck with a mass of 2,000 kg, at a rate of 3 m/s²?

Mathematics
2 answers:
ozzi3 years ago
7 0
6000N

reason: according to Newton’s second law of motion, Force = Mass x Acceleration
using this, multiply 2000 by 3 to get 6000
RSB [31]3 years ago
4 0
2,000 kg at a rate of 3 miles per second to the second square
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Ymorist [56]

Answer:

[6.5,-7.25]

Step-by-step explanation:

Given the partitioning ratio as 3:1

#Find the length of the x-coordinate and multiply by the ratio:

x length=9--1=10

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#We subtract 2.5 from the x-max to get the point=9-2.5=6.5

#Find the length of the y-coordinate and multiply by the ratio:

x length=-9--2=-7

=>\frac{1}{4}\times -7=-1.75

#We subtract -1.75 from the y-max to get the point=-9--1.75=-7.25

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3 years ago
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Step-by-step explanation:

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2 years ago
Two cargo ships spot a signal fire on a small island. The captains know they are 140 feet
Irina18 [472]

The distance from Ship B to the signal fire at point C is 405.4 \mathrm{ft}

Explanation:

It is given that two ships A and B are at a distance 140 ft from each other.

The angle formed by ship A is 82º and the angle formed by ship B is 78º.

To determine the distance from ship B to the signal fire at point C, we need to know the another angle.

Hence, we have,

\begin{aligned}\angle A+\angle B+\angle C &=180^{\circ} \\82^{\circ}+78^{\circ}+\angle C &=180^{\circ} \\160^{\circ}+\angle C &=180^{\circ} \\\angle C &=20^{\circ}\end{aligned}

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\frac{\sin A}{a}=\frac{\sin C}{c}

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Simplifying, we get,

a=\frac{0.9903 \times 140}{0.3420}

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