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emmainna [20.7K]

2 years ago

15

Someone pls help me I will make you as brain

1 answer:

earnstyle [38]2 years ago

8 0

The answer is (-4,0)

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Which of the following describes the graph y=[x-2]?

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3 years ago

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Harrison has $9.30 in his coin collection all in pennies and dimes the number of dimes is three times the number of pennies how

Vsevolod [243]

Answer:

Number of Pennies = 30

Number of Dimes = 90

Step-by-step explanation:

Let the number of pennies be p and number of dimes be d

We can write 2 equations and use substitution method to solve.

<u>Total value of all the coins is 9.30:</u>

We can write:

0.01p + 0.1d = 9.30

Note: value of penny is 0.01 and dime is 0.1, in dollars

<u>Number of dimes is 3 times number of pennies:</u>

We can write:

d = 3p

Now putting 2nd equation in first and solving for p:

0.01p + 0.1(3p) = 9.30

0.01p + 0.3p = 9.30

0.31 p = 9.30

p = 9.30 /0.31

p = 30

Now we know d = 3p, so d = 3 (30) = 90

Hence

Number of Pennies = 30

Number of Dimes = 90

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3 years ago

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Trava [24]

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https://www.mathpapa.com/algebra-calculator.html

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WHAT IS 5 TIMES 5 IN MATH

sergij07 [2.7K]

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Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)

vagabundo [1.1K]

Answer:

Considering the given equation $y = log_{3}x\\$

And the ordered pairs in the format $(x, y)$

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For $(\frac{1}{3}, a_{0} )$

$x=\frac{1}{3}$

$y=a_{0}$

$y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1$

So the ordered pair will be $(\frac{1}{3}, -1 )$

For $(1, a_{1} )$

$x=1$

$y=a_{1}$

$y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0$

So the ordered pair will be $(1, 0 )$

For $(3, a_{2} )$

$x=3$

$y=a_{2}$

$y = log_{3}x\\y = log_{3}3\\y = 1$

So the ordered pair will be $(3, 1 )$

For $(9, a_{3} )$

$x=9$

$y=a_{3}$

$y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2$

So the ordered pair will be $(9, 2 )$

For $(27, a_{4} )$

$x=27$

$y=a_{4}$

$y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3$

So the ordered pair will be $(27, 3 )$

For $(81, a_{5} )$

$x=81$

$y=a_{5}$

$y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4$

So the ordered pair will be $(81, 4 )$

4 0

3 years ago