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3 years ago

What is the mode of the list of numbers below? Choose ALL answers that are correct. 6, 1, 5, 2, 6, 5, 2, 6, 5

1 answer:

5 0

Rearrange the numbers in order from least to greatest:

<span>6, 1, 5, 2, 6, 5, 2, 6, 5

1, 2, 2, 5, 5, 5, 6, 6, 6

The number 1 is used once. The number 2 is used twice. Numbers 5 and 6 are used three times.

The mode is the number that is represented most in a set of numbers. Since 5 and 6 are both represented three times, these numbers will be the mode for this set.

The answers are C. 5 and D. 6.</span>

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Mr. James has cylindrical beakers that measure 4 inches in diameter and 9 inches high. What is the volume contained within the b

goblinko [34]

So 4 inches diameter result the radius is 4/2 = 2 inches

area of base = pir^2 = 3,14*2^2 = 3,14*4 = 12,56 inches squared

volume = area of base *height

V = 12,56 *9 = 113,04 so rounded 113,05 inches cubed

hope this will help you

3 0

3 years ago

Find the Area of the figure below, composed of an isoceles trapezoid and one

MAVERICK [17]

Answer:

the total area is 15.6 square units

Step-by-step explanation:

hello,

you can find the total area dividing the shape into two known shapes

total area= area of the trapezoid +area of the semicircle

then

step one

find the area of the isosceles trapezoid using

$A=\frac{a+b}{2}*h$

where

a is the smaller base

b is the bigger base

h is theheight

A is the area

let

a=2

b=5

h=4

put the values into the equation

$A=\frac{a+b}{2}*h\\A=\frac{5+2}{2}*4\\A=3.5*4\\A=14$

Step two

find the area of the semicircle

the area of a circle is given by

$A_{c}=\pi \frac{d^{2}}{4}\\$

but, we need the area of half circle, we need divide this by 2

$A_{semic}=\frac{ \pi \frac{d^{2}}{4}}{2}\\A_{semic}= \pi \frac{d^{2}}{8}$

now the diameter of the semicircle is 2, put this value into the equation

$A_{semic}= \pi \frac{2^{2}}{8}\\\\A_{semic}= \pi \frac{1}{2}\\ A_{semic}=\frac{\pi }{2}\\$

find the total area

total area= area of the trapezoid +area of the semicircle

$total\ area= 14+\frac{\pi }{2} \\total\ area=15.6$

so, the total area is 15.6 square units

Have a good day.

5 0

3 years ago

Helppppp with this. What do I have to do?

vaieri [72.5K]

You need to use the grids to draw rectangles which meet the requirements to help you put the answers in on the right.

1) Short side of 7 and long side of 9.

2) Short side of 9 and long side of 10.

3) Short side of 3 and long side of 8.

4) Short side of 4 and long side of 9.

5) Short side of 3 and long side of 5.

6) Short side of 6 and long side of 8.

7) Short side of 1 and long side of 2

8) Both sides 10 (this is technically a square).

9) Short side of 6 and long side of 9.

10) Short side of 7 and long side of 8.

11) Short side of 2 and long side of 3.

12) Short side of 6 and long side of 9.

You can draw these a few different ways to still get a correct result, so above are just one way of doing it.

5 0

3 years ago

What is the domain of y = √x^2-1?

andriy [413]

X can be -1 or 1 for the square root to be 0

The correct option is a

7 0

3 years ago

Read 2 more answers

What else would need to be congruent to show that AABC=A DEF by the

Pepsi [2]

Answer:

D. AC ≅ DF

Step-by-step explanation:

According to the AAS Theorem, two triangles are considered congruent to each other when two angles and a mon-included side of one triangle are congruent to two corresponding angles and a corresponding non-included side of the other.

Thus, in the diagram given:

<A and <B in ∆ABC are congruent to corresponding angles <D and <E in ∆DEF.

The only condition left to be met before we can conclude that both triangles are congruent by the AAS Theorem is for a mon-included side AC to be congruent to corresponding non-included side DF.

So, AC ≅ DF is what is needed to make both triangles congruent.

7 0

3 years ago