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Morgarella [4.7K]
3 years ago
7

What is the smallest number 13, 0.13, 1.03, 0.103, 1.3

Mathematics
2 answers:
stiv31 [10]3 years ago
6 0
The smallest is 0.103. Hope this helps.
kiruha [24]3 years ago
5 0
The smallest number of the group is .103

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PLEASE HELP AND HURRY
Inessa [10]

Answer:

4.75x=54+2.5x    x=24

Step-by-step explanation:

x=Number of games

4.75x=54+2.5x

Subtract 2.5x from both sides:

2.25x=54

Divide both sides by 2.25:

x=24

6 0
3 years ago
The mpg (miles per gallon for a certain compact car is normally distributed with a mean of 31 and a standard deviation of 0.8. w
lesantik [10]
For this Q:

mean=31
st.dev.=0.8
x=32

Calculate z-score:
z=(x-m)/s = (32-31)/0.8=1.25

This z-score value corresponding to the probability of 0.8944

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6 0
3 years ago
Pls help pls pls pls
Romashka [77]

Answer: A don't get confused by b

Step-by-step explanation:

5 0
3 years ago
What is the gcf of 15 and 10
Zielflug [23.3K]
The gcf of 15 and 10 is 5
7 0
3 years ago
Read 2 more answers
I have nooooo clue, please help
Aleksandr-060686 [28]

Answer:

case a) x^{2}=3y ----> open up

case b) x^{2}=-10y ----> open down

case c) y^{2}=-2x ----> open left

case d) y^{2}=6x ----> open right

Step-by-step explanation:

we know that

1) The general equation of a vertical parabola is equal to

y=a(x-h)^{2}+k

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open upward and the vertex is a minimum

If a<0 ----> the parabola open downward and the vertex is a maximum

2) The general equation of a horizontal parabola is equal to

x=a(y-k)^{2}+h

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open to the right

If a<0 ----> the parabola open to the left

Verify each case

case a) we have

x^{2}=3y

so

y=(1/3)x^{2}

a=(1/3)

so

a>0

therefore

The parabola open up

case b) we have

x^{2}=-10y

so

y=-(1/10)x^{2}

a=-(1/10)

a

therefore

The parabola open down

case c) we have

y^{2}=-2x

so

x=-(1/2)y^{2}

a=-(1/2)

a

therefore

The parabola open to the left

case d) we have

y^{2}=6x

so

x=(1/6)y^{2}

a=(1/6)

a>0

therefore

The parabola open to the right

3 0
3 years ago
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