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4 years ago

What is the smallest number 13, 0.13, 1.03, 0.103, 1.3

Mathematics

2 answers:

stiv31 [10]4 years ago

6 0

The smallest is 0.103. Hope this helps.

kiruha [24]4 years ago

5 0

The smallest number of the group is .103

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fgiga [73]

Answer:

The length of side of largest square is 15 inches

Step-by-step explanation:

The given suares are when joined in the way as shown in picture their sides form a right agnled triangle.

Area of square 1 and perimeter of square 2 will be used to calculate the sides of the triangle.

So,

<u>Area of square 1: 81 square inches</u>

$s^2 = A\\s^2 = 81\\\sqrt{s^2} = \sqrt{81}\\s = 9$

<u>Perimeter of square 2: 48 inches</u>

$4*side = P\\4* side = 48\\side = \frac{48}{4}\\side = 12\ inches$

We can see that a right angled triangle is formed.

Here

Base = 12 inches

Perpendicular = 9 inches

And the side of largest square will be hypotenuse.

Pythagoras theorem can be used to find the length.

$(H)^2 = (P)^2+(B)^2\\H^2 = (9)^2+(12)^2\\H^2 = 81+144\\H^2 = 225\\\sqrt{H^2} = \sqrt{225}\\H = 15$

Hence,

The length of side of largest square is 15 inches

5 0

3 years ago

14.

Tpy6a [65]

Its C. 113 ft because the height and the perimider of the trinagle

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3 years ago

A rectangular locker is 1 4/5feet long, 1 4/5 feet wide, and 1 foot tall.The locker has a capacity of BLANK

alexandr1967 [171]

V=xyz where x,y,z are the three dimensions...

V=(1 4/5)(1 4/5)1

V=(9/5)(9/5)=81/25

V=3 6/25 ft^3

3 0

3 years ago

Please help me guys, its five questions

ruslelena [56]

Answer:

1. A 2.d 3.b 4.a 5. c

Step-by-step explanation:

7 0

3 years ago

Find the exact value of cos(7\pi /12)

Naya [18.7K]

7π/12 lies in the second quadrant, so we expect cos(7π/12) to be negative.

Recall that

$\cos^2x=\dfrac{1+\cos(2x)}2$

which tells us

$\cos\left(\dfrac{7\pi}{12}\right)=-\sqrt{\dfrac{1+\cos\left(\frac{7\pi}6\right)}2}$

Now,

$\cos\left(\dfrac{7\pi}6\right)=-\cos\left(\dfrac\pi6\right)=-\dfrac{\sqrt3}2$

and so

$\cos\left(\dfrac{7\pi}{12}\right)=-\sqrt{\dfrac{1-\frac{\sqrt3}2}2}=\boxed{-\dfrac{\sqrt{2-\sqrt3}}2}$

7 0

3 years ago