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labwork [276]
4 years ago
6

An ant is crawling along a straight wire, which we shall call the x axis, from A to B to C to D (which overlaps A), as shown in

the figure below. O is the origin. Suppose you take measurements and find that AB is 62.0 cm, BC is 42.0 cm, and AO is 3.00 cm. What is the ant’s position at point B?
Mathematics
1 answer:
Kipish [7]4 years ago
4 0
In your problems that ask the position of the ant labeled as B if they are crawling in a straight wire which shall call the x axis form a to b to c to d the answer to you problem base on my calculation and by understanding the best answer would be 59cm
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Which statement correctly compares the mean number of students for the data in the plots?
satela [25.4K]

Answer:

<em><u>"There are about 2 more students in each class at Oak Middle School than at Poplar Middle School."</u></em>

Step-by-step explanation:

We need to compute the mean for each.

<u>Poplar Middle School:</u>

Lets list the numbers

20,20,20,21,21,21,21,21,22,22,22,22,22,22,22,23,23,23,23,24

The average is sum of all divided by number of numbers, that will be:

435/20 = 21.75

<u>Oak Middle School:</u>

The numbers are:

20,21,21,22,22,23,23,23,23,24,24,24,25,25,26,26,27,27,28,29

The average is sum divided by number of numbers, that will be:

483/20 = 24.15

The difference in mean is:

24.15 - 21.75 = 2.4

We can say, that is about 2 more students in Oak Middle School, correct answer choice is "2nd answer choice" - <em><u>"There are about 2 more students in each class at Oak Middle School than at Poplar Middle School."</u></em>

7 0
3 years ago
How many factors of muliplication does 20 have
amid [387]

Here are some factors of 20!

1x20=20

2x10=20

4x5=20

5x4=20


Therefore there are 4 factors of 20.

4 0
3 years ago
Read 2 more answers
Suppose the null hypothesis, H0, is: Darrell has enough money in his bank account to purchase a new television. What is the Type
seropon [69]
<h2>Answer with explanation:</h2>

In statistics, The Type II error occurs when the null hypothesis is false, but fails to be rejected.

Given : Suppose the null hypothesis, H_0, is: Darrell has enough money in his bank account to purchase a new television.

Then , Type II error in this scenario will be when the null hypothesis is false, but fails to be rejected.

i.e. Darrell has not enough money in his bank account to purchase a new television but fails to be rejected.

3 0
3 years ago
Consider the following problem: A farmer with 750 ft of fencing wants to enclose a rectangular area and then divide it into four
gregori [183]

Answer and step-by-step explanation:

For any rectangle, the one with the largest area will be the one whose dimensions are as close to a square as possible.

However, the dividers change the process to find this maximum somewhat.

Letting x represent two sides of the rectangle and the 3 parallel dividers, we have 2x+3x = 5x.

Letting y represent the other two sides of the rectangle, we have 2y.

We know that 2y + 5x = 750.

Solving for y, we first subtract 5x from each side:

2y + 5x - 5x = 750 - 5x

2y = -5x + 750

Next we divide both sides by 2:

2y/2 = -5x/2 + 750/2

y = -2.5x + 375

We know that the area of a rectangle is given by

A = lw, where l is the length and w is the width.  In this rectangle, one dimension is x and the other is y, making the area

A = xy

Substituting the expression for y we just found above, we have

A = x(-2.5x+375)

A = -2.5x² + 375x

This is a quadratic equation, with values a = -2.5, b = 375 and c = 0.

To find the maximum, we will find the vertex.  First we find the axis of symmetry, using the equation

x = -b/2a

x = -375/2(-2.5) = -375/-5 = 75

Substituting this back in place of every x in our area equation, we have

A = -2.5x² + 375x

A = -2.5(75)² + 375(75) = -2.5(5625) + 28125 = -14062.5 + 28125 = 14062.5

6 0
3 years ago
Sam and Jeremy have ages that are consecutive odd integers. The product of their ages is 783, which equation could be used to fi
stepladder [879]
(2x+1)=Jeremy´s age
(2x+3)=Sam´s age.
we suggest this equation:
(2x+1)(2x+3)=783
4x²+6x+2x+3=783
4x²+8x-780=0
x²+2x-195=0

We solve this quadratic equation:
x=[-2⁺₋√(4-4*1*(-195))]/2=(-2⁺₋28)/2

x₁=(-2-28)/2=-15 this solution is not valid.
x₂=(-2+28)/2=13

Jeremy´s age=2x+1=2*13+1=27
Sam´s age=2x+3=2*13+3=29



7 0
3 years ago
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