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igor_vitrenko [27]
3 years ago
5

Do other plants have seasons? explain

Physics
1 answer:
erik [133]3 years ago
7 0
Any planet with a tilted rotation axis has seasons.
If the axis of rotation is not "straight up and down", then the sun shines
more directly on one hemisphere for half of the planet's year, and more
directly on the other hemisphere during the other half of the year.  That's
what it takes to make seasons.
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Which of the following is not a subatomic particle?
Fynjy0 [20]
D. Nucleus because it is not a part of the group.
7 0
4 years ago
A train car, which has a mass of 2000 kg, is rolling along with a velocity of 20 m/s East. It
Thepotemich [5.8K]

10m/s East

Explanation:

p=mv

m1v1 = m2v

p = m1v1

2000kg*(20m/s) = 40000kg*m/s

Add the two masses together for m2

p = m2v2

40000kg*m/s = 4000kg * v2

v2 = 10m/s

7 0
3 years ago
Drag each tile to the correct box.
hoa [83]

Federal reserve decreases the required reserve ratio.

Banks have more money to lend

Money supply increases

Interest rates fall

Households and business take out more loans

Purchases and investments increases.

Explanation:

There are two types of monetary policies, Expansionary and Contractionary.

The government decides the monetary policy based on the economy of a country. The government will have expansionary monetary policy when it requires more money in the economy. Interest rates are lowered and money supply is increased. This results increase in Gross Domestic products of the country and the economy strengthens.

3 0
3 years ago
A truck covers 32.0 m in 8.70 s while smoothly slowing down to final speed of 2.10 m/s. (a) Find its original speed. Incorrect:
Natalka [10]

Explanation:

Given that,

Distance covered, d = 32 m

Time, t = 8.7 m

Final speed of the truck, v = 2.1 m/s

(a) Let a is the acceleration and u is the original speed of the truck.

Using first equation of kinematics as :

v=u+at

2.1=u+8.7a..............(1)

Using second equation of kinematics as :

d=ut+\dfrac{1}{2}at^2

32=u(8.7)+\dfrac{1}{2}a(8.7)^2...........(2)

On solving equation (1) and (2) we get :

Original speed, u=5.25\ m/s

(b) Acceleration, a=-0.36\ m/s^2

Hence, this is the required solution.

7 0
4 years ago
You shoot an arrow into the air. Two seconds later (2.00 s) the arrow has gone straight upward to a height of 35.0 m above its l
sdas [7]

This question can be solved by using the equations of motion.

a) The initial speed of the arrow is was "9.81 m/s".

b) It took the arrow "1.13 s" to reach a height of 17.5 m.

a)

We will use the second equation of motion to find out the initial speed of the arrow.

h= v_it + \frac{1}{2}gt^2\\

where,

vi = initial speed = ?

h = height = 35 m

t = time interval = 2 s

g = acceleration due to gravity = 9.81 m/s²

Therefore,

35\ m = (v_i)(2\ s)+\frac{1}{2}(9.81\ m/s^2)(2\ s)^2\\\\v_i(2\ s)=19.62\ m\\\\v_i = \frac{19.62\ m}{2\ s}

<u>vi =  9.81 m/s</u>

b)

To find the time taken by the arrow to reach 17.5 m, we will use the second equation of motion again.

h= v_it + \frac{1}{2}gt^2\\

where,

g = acceleration due to gravity = 9.81 m/s²

h = height = 17.5 m

vi = initial speed = 9.81 m/s

t = time = ?

Therefore,

17.5 = (9.81)t+\frac{1}{2}(9.81)t^2\\4.905t^2+9.81t-17.5=0

solving this quadratic equation using the quadratic formula, we get:

t = -3.13 s (OR) t = 1.13 s

Since time can not have a negative value.

Therefore,

<u>t = 1.13 s</u>

Learn more about equations of motion here:

brainly.com/question/20594939?referrer=searchResults

The attached picture shows the equations of motion in the horizontal and vertical directions.

4 0
2 years ago
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