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rosijanka [135]
4 years ago
11

The process of _________________ replaces a faulty gene with a normal working gene.

Physics
2 answers:
ch4aika [34]4 years ago
4 0
DNA transcription. ....
strojnjashka [21]4 years ago
4 0
<span>The process of  <u>B.GENE THERAPY </u>replaces a faulty gene with a normal working gene. 


As stated in your previous post
</span>
You might be interested in
Which statement correctly describes the reactivity of noble gases according to the octet rule
algol13

Their atoms have eight electrons in their valence shells, so noble gases are very unreactive.

Explanation:

The octet rule state that atoms tend to complete their last energy levels with eight electrons, and that this configuration make them very stable and unreactive.

Noble gases are characterized as unreactive atoms, and this is associated with the fact that they have a complete valence shell, it means that they have eight electrons on it (they follow the octet rule).

Atoms with less electrons on their valence shells tend to react with another atom, forming bonds, to complete their valence shells (with eight electrons).

<h2>---</h2>

Hope this helps you! Have a great day and or night love <3

3 0
1 year ago
Read 2 more answers
There are two high and two low tides each day. this is a result of which earth movement
Flauer [41]
The Earth's spin in its axis each 24 hours
7 0
3 years ago
A power supply maintains a potential difference of 52.3 V 52.3 V across a 1570 Ω 1570 Ω resistor. What is the current in the res
irakobra [83]

Answer:

0.033 A

Explanation:

Current: This can be defined as the rate of flow of electric charge in a circuit.

The S.I unit of current is Ampere (A)

From Ohm's law.

V = IR ............................ Equation 1

Where V = Potential difference, I = current, R = resistance.

Making I the subject of the equation,

I = V/R................... Equation 2

Given: V = 52.3 V, R = 1570 Ω

Substitute into equation 2

I = 52.3/1570

I = 0.033 A.

Hence the current in the resistor = 0.033 A

6 0
3 years ago
A hoop is rolling without slipping along a horizontal surface with a forward speed of 5.50 m/s when it starts up a ramp that mak
Burka [1]

Answer:

v_f = 4.22 m/s

Explanation:

As we know by energy conservation

initial total energy = final total energy

so we have

\frac{1}{2}mv^2 + \frac{1}{2}I\omega^2 = \frac{1}{2}mv_f^2 + \frac{1}{2}I\omega_f^2 + mgL sin\theta

so we have

v = R \omega

I = mR^2

mv_i^2 = mv_f^2 + mgL sin\theta

5.50^2 = v_f^2 + (9.81)(3) sin25

30.25 - 12.43 = v_f^2

v_f = 4.22 m/s

5 0
4 years ago
An object is placed in front of a convex mirror with a radius of curvature of magnitude 10 cm. The mirror produces an image that
jek_recluse [69]

Answer:

u = - 20 cm

m =\frac{1}{5}

Given:

Radius of curvature, R = 10 cm

image distance, v = 4 cm

Solution:

Focal length of the convex mirror, f:

f = \frac{R}{2} = \frac{10}{2} = 5 cm

Using Lens' maker formula:

\frac{1}{f} = \frac{1}{u} + \frac{1}{v}

Substitute the given values in the above formula:

\frac{1}{5} = \frac{1}{u} + \frac{1}{4}

\frac{1}{u} = \frac{1}{5} - \frac{1}{4}

u = - 20 cm

where

u = object distance

Now, magnification is the ratio of image distance to the object distance:

magnification, m =\frac{|v|}{|u|}

magnification, m =\frac{|4|}{|-20|}

m =\frac{4}{20}

m =\frac{1}{5}

4 0
3 years ago
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