Answer:
ΔS= -1 J/K
Explanation:
Given data
Heat Q= -470J
Temperature T=470 K
To find
Entropy change ΔS
Solution
We know that the entropy change of system is ΔS is given by
ΔS=Q/T
We have take heat value Q as negative because the heat is removed from heat reservoir
So
ΔS=(-470J/470K)
ΔS= -1 J/K
C. The forces on an object traveling at terminal velocity are balanced.
Answer:
v = K √(E / ρ)
Explanation:
Modulus of elasticity has units of N/m², or kg/m/s².
Density has units of kg/m³.
Velocity has units of m/s.
If we divide modulus of elasticity by density, we can eliminate kg:
E / ρ = [kg/m/s²] / [kg/m³]
E / ρ = [m²/s²]
Taking the square root gets us units of velocity:
√(E / ρ) = [m/s]
Multiply by the constant K:
v = K √(E / ρ)
X -> Y + 2Z
So there are 2 different particles. 1 mol of X produces
1 mol of Y and 2 moles of Z.
Kps = [Y] [Z]^2
We will call “s” (solubility) the molarity of X
So the molarity of Y+ is also “s” (same number)
And the molarity of Z is “2s” (twice as much)
Kps = s*(2s)^2 = s*4s^2=4s^3
If s is multiplied by 2:
Kps = 4*(2s)^3=4*2^3*s^3=4*8*s^3
So Kps is multiplied by 8.
A c and e are correct but b and d are incorrect. i hope this helped
