Question

Help me to take this

Answer 1

Step-by-step explanation:

$\int \bigg( - \frac{2}{7} {x}^{3} - 4 {x}^{4} - 2x \bigg)dx \\ \\ = - \frac{2}{7}\int {x}^{3}dx - 4 \int {x}^{4}dx - 2\int x dx \\ \\ = - \frac{2}{7} \times \frac{ {x}^{4} }{4} - 4 \times \frac{ {x}^{5} }{5} - 2 \times \frac{ {x}^{2} }{2} + c \\ \\ = - \frac{{x}^{4} }{14} - \frac{4}{5} {x}^{5} - {x}^{2} + c$