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liberstina [14]
3 years ago
5

Plz help me 10 points!

Mathematics
1 answer:
Nookie1986 [14]3 years ago
8 0
BAC=ABD. therefore ABD = 20°
BDA = 180° - 20° -20° = 140°
BDC = 180° - 140° = 40°
BCD = 180° - 40° - 20° = 120°
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Which number has more than two factors? <br> A. 19<br> B. 23<br> C. 25<br> D. 29
Whitepunk [10]

The answer would be 25 because all of the others are prime numbers, meaning they can only be divided by themselves and 1. So it would be C.
4 0
3 years ago
2. Calculate the angular speed of the 26-inch bicycle rotating at 200 revolutions per minute. Express your answer in radians per
Alexus [3.1K]
The angular velocity for this problem is given by:
 Angular speed = 200 rev / min
 The first thing you should keep in mind is the following conversion:
 1 rev = 2π radians
 Applying the conversion we have:
 Angular speed = 200 * (2π)
 Rewriting:
 Angular speed = 200 * (2 * 3.14)
 Angular speed = 1256 radians / minutes
 Answer:
 
the angular speed is:
 
Angular speed = 1256 radians / minutes
4 0
4 years ago
Solve for y 16y^2-25=0
Pepsi [2]

Answer:

\large\boxed{x=-\dfrac{5}{4}\ \vee\ x=\dfrac{5}{4}}

Step-by-step explanation:

16y^2-25=0\\\\METHOD\ 1:\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\16=4^2\ \text{and}\ 25=5^2\ \text{therefore we have}\\\\4^2y^2-5^2=0\\\\(4y)^2-5^2=0\\\\(4y-5)(4y+5)+0\iff4y-5=0\ \vee\ 4y+5=0\\\\4y-5=0\qquad\text{add 5 to both sides}\\4y=5\qquad\text{divide both sides by 4}\\\boxed{y=\dfrac{5}{4}}\\\\4y+5=0\qquad\text{subtract 5 from both sides}\\4y=-5\qquad\text{divide both sides by 4}\\\boxed{x=-\dfrac{5}{4}}

METHOD\ 2:\\\\16y^2-25=0\qquad\text{add 25 to both sides}\\\\16y^2=25\qquad\text{divide both sides by 16}\\\\y^2=\dfrac{25}{16}\to y=\pm\sqrt{\dfrac{25}{26}}\\\\y=-\dfrac{\sqrt{25}}{\sqrt{16}}\ \vee\ x=\dfrac{\sqrt{25}}{\sqrt{16}}\\\\\boxed{y=-\dfrac{5}{4}\ \vee\ x=\dfrac{5}{4}}

7 0
3 years ago
Read 2 more answers
1+1 equals 2 plus 3 get brainlist if u answer first
dusya [7]
Cool thanks bro I appreciate it
7 0
3 years ago
Read 2 more answers
4w^2+49=-28w solve for w<br><br> plz answer
boyakko [2]

Move all terms to one side

4w^2 + 49 + 28w = 0

Rewrite 4w^2 + 49 + 28w in the form a^2 + 2ab + b^2, where a = 2w and b = 7

(2w)^2 + 2(2w)(7) + 7^2 = 0

Use the Square of Sum: (a + b)^2 = a^2 + 2ab + b^2

(2w + 7)^2 = 0

Take the square root of both sides

3w + 7 = 0

Subtract 7 from both sides

2w = -7

Divide both sides by 2

<u>w = -7/2</u>

3 0
3 years ago
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