C
This is because none of the numbers can be divided by any number other than themselves or 1.
Answer:
63.51 m
Step-by-step explanation:
TOA
let o be the height of the building
tan31°=o/110m
0=110m tan31°
o=63.51m
Since they are right triangles use Pythagorean Theorem.
a^2 + b^2 = c^2 where c is the hypotenuse.
a. 12^2 + b^2 = 13^2
144 + b^2 = 169
subtract 144 from both sides
b^2 = 25
take the square root of both sides
t = 5 This is also know as a Pythagorean Triple 5-12-13
b. a^2 + 9^2 = 12^2
a^2 + 81 = 144
subtract 81 from both sides
a^2 = 63
take the square root of both sides
a = √63
a = √(9 * 7)
a = 3√7
c. 6^2 + 9^2 = c^2
36 + 81 = c^2
117 = c^2
take the square root of each side
c = √117
c = √(9*13)
x = 3√13
Answer:
Area of square pyramid is
.
Step-by-step explanation:
Diagram of the given scenario is shown below,
Given that,
The Great Pyramid in Giza, Egypt is a square pyramid. The area of base shape is made up with square is
. The side of the square is
and The height of each triangle is
.
So, Area of Square shape = 
Side of square = 
Height of each triangle = 
Finding the Height of triangular shape which is here known as slant height.
In Δ ABO, applying Right angle pythagorean Theorem,
Base
= 
Height
= 
Now,
∴ 
⇒ 
⇒ 
⇒ 
⇒ 
Then,
Area of square pyramid = 
=
= 
= 
= 
Hence, Area of square pyramid is
.