write the sum of the numbers as the product of their greatest common factor and another sum for 15 81

Identify the error by providing a brief description. Then, complete the problem correct

Ipatiy [6.2K]

Answer:

True answer: -24

Step-by-step explanation:

Showing the error

-16-2(-2) – 12 First you need to multiply

8(-2) - 12 The error here is that the wrong numbers are multiplied together

-16-12 Add the negatives together

-28 Your answer (the incorrect one)

The correct way of solving it

-16 -2(-2) - 12 Multiply into the parenthesis

-16 + 4 -12 Add the first two numbers

-12 - 12 Add the numbers together

-24 The answer

8 0

2 years ago

Tom bought 3 packages of Skittles for $1.25 each. How much did he spend?

polet [3.4K]

Answer:

Tom spent $3.75 of Skittles

Step-by-step explanation:

If each Skittle packet was $1.25, then if that is multiplied by 3, the product of the equation is, 3 dollars and 75 cents/$3.75

1.25 x 3 = 3.75

7 0

2 years ago

Read 2 more answers

An ant looks to the top of a bulding at an angle of elevation of 32°. The ant then walks an additional 66 feet from the edge of

Keith_Richards [23]

Let the height of the building be x. Let the initial distance of the ant from the building be y, then
tan 32 = x/y
y = x/tan 32 . . . . . . . . (1)
tan 22 = x/(y + 66)
y tan 22 + 66 tan 22 = x
y = (x - 66 tan 22)/tan 22 . . . . . . . . (2)
Equating (1) and (2), we have
x/tan 32 = (x - 66 tan 22)/tan 22
x tan 22 = x tan 32 - 66 tan 22 (tan 32)
x(tan 32 - tan 22) = 66 tan 22 (tan 32)
x = (66 tan 22 (tan 32))/(tan 32 - tan 22) = 66(0.4040)(0.6249)/(0.6249 - 0.4040) = 16.6626/0.2208 = 75.4

Therefore, the height of the building is 75.4 feet.

8 0

2 years ago

An insurance company selected a random sample of 500 clients under 18 years of age and found that 180 of them had had an acciden

Butoxors [25]

Answer:

a) The pooled proportion is p=0.3.

b) P-value = 0.000078

c) Lower bound = 0.0556

d) Upper bound = 0.1644

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the accident proportions differ between the two age groups .

Then, the null and alternative hypothesis are:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2\neq 0$

The significance level is 0.05.

The sample 1, of size n1=500 has a proportion of p1=0.36.

$p_1=X_1/n_1=180/500=0.36$

The sample 2, of size n2=600 has a proportion of p2=0.25.

$p_1=X_1/n_1=150/600=0.25$ .

The difference between proportions is (p1-p2)=0.11.

$p_d=p_1-p_2=0.36-0.25=0.11$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{180+150}{500+600}=\dfrac{330}{1100}=0.3$

The standard error for the difference between proportions can now be calculated as:

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.3*0.7}{500}+\dfrac{0.3*0.7}{600}}\\\\\\s_{p1-p2}=\sqrt{0.00042+0.00035}=\sqrt{0.00077}=0.0277$

Then, we can calculate the z-statistic as:

$z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.11-0}{0.0277}=\dfrac{0.11}{0.0277}=3.964$

This test is a two-tailed test, so the P-value for this test is calculated as (using a z-table):

$P-value=2\cdot P(t>3.964)=0.000078$

As the P-value (0.000078) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the accident proportions differ between the two age groups.

If we want to calculate the bounds of a 95% confidence interval, we start by calculating the margin of error.

For a 95% CI, the critical value for z is z=1.96.

Then, the margin of error is:

$MOE=z \cdot s_{p1-p2}=1.96\cdot 0.0277=0.0544$

Then, the lower and upper bounds of the confidence interval are:

$LL=(p_1-p_2)-z\cdot s_{p1-p2} = 0.11-0.0544=0.05561\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= 0.11+0.0544=0.16439$

The 95% confidence interval for the population mean is (0.0556, 0.1644).

5 0

2 years ago

A rectangle has a length of x inches and a width 2 inches less than the length. If the dimensions were doubled, what would be th

Gelneren [198K]

Answer:

Option (4)

Step-by-step explanation:

Area of a rectangle = Length × width

If the dimensions of the given rectangle is doubled,

Area of the new rectangle = 2(Length) × 2(width)

= 4(Length × width)

= 4(x)(x - 2)

= 4[x² - 2x]

= 4x² - 8x

Therefore, Option (4) will be the correct option.

8 0

2 years ago