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2 years ago

write the sum of the numbers as the product of their greatest common factor and another sum for 15 81

Mathematics

1 answer:

velikii [3]2 years ago

8 0

15 + 81 = 3(5 + 27).

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I got 57.12, but it’s not an answer...I am confusion

Setler [38]

Check the picture below.

$\bf \stackrel{\textit{area of the semicircle}}{\frac{\pi r^2}{2}}~~~~+~~~~\stackrel{\textit{area of the triangle}}{\frac{1}{2}bh}
\\\\\\
\stackrel{\textit{area of the semicircle}}{\frac{\pi 4^2}{2}}~~~~+~~~~\stackrel{\textit{area of the triangle}}{\frac{1}{2}(12)(8)}
\\\\\\
8\pi +48\qquad \approx\qquad 73.1327412287$

4 0

3 years ago

Carlos tiene 3 chocolates más que mariana, mariana tiene 3 chocolates más que verónica y verónica tiene 3 chocolates más que lui

Elden [556K]

Carlos : 23.5

Mariana : 20.5

Verónica : 17.5

Luis : 14.5

I THINK !!!
I DONT KNOW IF IM RIGHT!!!!!

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2 years ago

X over 2 +2= 15 two step equations

Fed [463]

Answer:

$\boxed{\boxed{\sf x=84}}$

Step-by-step explanation:

$\sf \cfrac{x}{6} +2=16$

Multiply both sides of the equation by 6:

$\sf x+12=96$

Subtract 12 from both sides:

$\sf x=96-12$

Subtract 12 from 96:

$\sf x=84$

_________________________________

3 0

1 year ago

Read 2 more answers

Help please!!!!!!!!!!!!! Explain if possible

iris [78.8K]

Answer is C.
For every option, sub in the value and find the answer that matches the equation!

Example for option A, F(x) = x + 4 and G(x) = x²
G(F(x)) = G(x + 4) ーー> sub in the value of F(x)
Let's take the subbed in value, (x + 4) as x, and this x will be the x for G(x).

∴ Since G(x) is x²
G(x + 4) = (x + 4)² ーー> remember (x + 4) is represented as x.
= x² + 16
∴ You know that the answer is not A, do this for all options and you'll find the answer, C!

4 0

3 years ago

Simplify the given expression below 4/3-2i

ANTONII [103]

So-called simplifying, really means, "rationalizing the denominator", which is another way of saying, "getting rid of that pesky radical in the bottom"

$\bf \cfrac{4}{3-2i}\cdot \cfrac{3+2i}{3+2i}\impliedby \textit{multiplying by the conjugate of the bottom}
\\\\\\
\cfrac{4(3+2i)}{(3-2i)(3+2i)}\implies \cfrac{4(3+2i)}{3^2-(2i)^2}\implies \cfrac{4(3+2i)}{3^2-(4i^2)}\\\\
-------------------------------\\\\
recall\qquad i^2=-1\\\\
-------------------------------\\\\
\cfrac{4(3+2i)}{3^2-(4\cdot -1)}\implies \cfrac{4(3+2i)}{9+4}\implies \cfrac{12+8i}{13}\implies \cfrac{12}{13}+\cfrac{8}{13}i$

4 0

3 years ago

Read 2 more answers