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lorasvet [3.4K]
2 years ago
10

Change from $20 after spending $13.76

Mathematics
1 answer:
tamaranim1 [39]2 years ago
5 0
20 - 13.76 = 6.24

The change after spending $13.76 would be $6.24.
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Which of the following quartic functions has x=-1 and x=-2 as its only two real zeros
Brums [2.3K]
Quartic is 4th degree
the factors of an equation with roots r1,r2 is
(x-r1)(x-r2)
4th degree
it could be
(x-r1)¹(x-r2)³ or
(x-r1)²(x-r2)² or
(x-r1)³(x-r2)¹


roots or zeroes at x=-1 and x=-2
(x-(-1)) and (x-(-2))
(x+1) and (x+2)

the function could be factored into
(x+1)¹(x+2)³ or
(x+1)²(x+2)² or
(x+1)³(x+2)¹

expanded would be
x⁴+7x³+18x²+20x+9 or
x⁴+6x³+13x²+12x+4 or
x⁴+5x³+9x²+7x+2
one of those is the answer

4 0
3 years ago
Help with my math READ IT CARFULLY
Irina-Kira [14]

Sci = π . 2 . 2 = 12,56 ⇒ 1/2 Sc1 = 1/2 . 12,56 = 6,28

Srec = 6 . 4 = 24

S= 6,28 + 24 = 30,28

the answer is 30,28

ok done. Thank to me :>

8 0
2 years ago
What is the slope of the line that passes through the following points:<br> (4, -3), (-5, 10)
umka21 [38]

Answer:

-9/13

Step-by-step explanation:

The formula for slope is [ y2-y1/x2-x1 ].

10-(-3)/-5-4

13/-9

-9/13

Best of Luck!

5 0
3 years ago
Solve triangle ABC, when A= 6, B=10 and c=12
valentinak56 [21]
Use cosine rule,

cos(A)=(b^2+c^2-a^2)/(2bc)
=(10^2+12^2-6^2)/(2*10*12)
=13/15
A=29.926 degrees.................................(A)

cos(B)=(c^2+a^2-b^2)/(2ca)
=(12^2+6^2-10^2)/(2*12*6)
=5/9
B=56.251 degrees.................................(B)

cos(C)=(a^2+b^2-c^2)/(2ab)
=(6^2+10^2-12^2)/(2*6*10)
=-1/15
C=93.823 degrees.................................(C)

Check:29.926+56.251+93.823=180.0 degrees....ok
5 0
3 years ago
0647grams nearest tenth
balu736 [363]
1000 is the answer! hoped I helped
8 0
3 years ago
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