Answer:
C. (3, 3)
Step-by-step explanation:
Answer:
D: 101, 135, 131, 99, 138, 136, 140
Step-by-step explanation:
edg2020 (do not get this confused with the question: "which set contains no outliers"
Answer:
The mean is also increased by the constant k.
Step-by-step explanation:
Suppose that we have the set of N elements
{x₁, x₂, x₃, ..., xₙ}
The mean of this set is:
M = (x₁ + x₂ + x₃ + ... + xₙ)/N
Now if we increase each element of our set by a constant K, then our new set is:
{ (x₁ + k), (x₂ + k), ..., (xₙ + k)}
The mean of this set is:
M' = ( (x₁ + k) + (x₂ + k) + ... + (xₙ + k))/N
M' = (x₁ + x₂ + ... + xₙ + N*k)/N
We can rewrite this as:
M' = (x₁ + x₂ + ... + xₙ)/N + (k*N)/N
and (x₁ + x₂ + ... + xₙ)/N was the original mean, then:
M' = M + (k*N)/N
M' = M + k
Then if we increase all the elements by a constant k, the mean is also increased by the same constant k.
Square root of 11 because:
sqrt2^2 = 2
3^2 = 9
so C^2 or the hypotenuse would be the square root of 11
Answer:
21
Step-by-step explanation:
Negative times negative is positive.
-3(-7) = 21
