<span>gravitational potential energy : P
Gravity : g
Mass : m
height : h

P = mgh = 3 x 9.8 x 0.45 = 13.23 Joule

Potential energy is work , from the known formula

W = Fd ( work = force x distance )

W = P ( in case of potential energy height change)

F is the force acting on the body in case of ideal ramp , the only force acting is the weight of the body

F = mg ( not just <m> as the force is mg (Newton) gravity effect)

d is the displacement in direction of force, as we have considered the force to be the weight not it's component in direction of the ramp , the change in displacement is the change in height so

d = h

W = Fd = (F = mg) x (d = h) = mgh

W = mgh = P

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7 0

4 years ago

Adam uses coconut milk for the dessert.

Ivanshal [37]

So basically, since you know the equation and all of the dimensions, just plug in all of the numbers.

V = $\pi$ r^2 h
V = 3 [the radius is diameter / 2] 4^2 * 12
V = 3 * 16 * 12
V = 48 * 12
V = 576

So there is 576 cm cubed of milk inside of the can.

(Whether it's filled to the brim, probably not.)

I hope I helped! :)

5 0

3 years ago

Which expression is equivalent to Left-bracket log 9 + one-half log x + log (x cubed + 4) Right-bracket minus log 6? log StartFr

dybincka [34]

Answer:

$\log{\dfrac{3\sqrt{x}(x^3+4)}{2}}$

Step-by-step explanation:

$\log{9}+\dfrac{1}{2}\log{x}+\log{(x^3+4)}-\log{6}=\log{\left(\dfrac{9x^{\frac{1}{2}}(x^3+4)}{6}\right)}\\\\=\boxed{\log{\dfrac{3\sqrt{x}(x^3+4)}{2}}}\qquad\text{matches choice A}$

The applicable rules of logarithms are ...

log(ab) = log(a) +log(b)

log(a/b) = log(a) -log(b)

log(a^b) = b·log(a)

3 0

3 years ago

Help me I need to pass this

Paladinen [302]

Answer:

Eu axo q é antigo isso

Step-by-step explanation:

6 0

4 years ago