Answer:
1/2
Step-by-step explanation:
First, write out the product. Then, reduce as far as possible:
5 24 5(1)(4)(6)
----- * ------- = --------------- Here, the 5s cancel, and so we get:
16 15 5(3)(4)(4)
4(6)
----------
3(4)(4)
Here, the 4 in the numerator cancels out one of the 4s in the denominator:
6
------
12
and this last result reduces to 1/2.
Answer:
(230.21 ; 233.13)
Step-by-step explanation:
Given the data :
230.66, 233.05, 232.58, 229.48, 232.58
To calculate the 90% CI
WE obtain the mean and standard deviation of the sample data :
Mean of sample, ΣX /n = 1158.35/5 = 231.67
The standard deviation of the sample, s = 1.531 (Using calculator).
(The 90% Tcritical value, 2 sided, df = 4) = 2.132
The confidence interval, CI :
Mean ± Tcritical * s/√n
C.I = 231.67 ± (2.132 * (1.531/√5)
C. I = 231.67 ± 1.4597
(231.67 - 1.4597) ; (231.67 + 1.4597)
(230.21 ; 233.13)
Answer:
(a) The mean of the weight of the mice is 50.26 grams.
(b) The standard deviation of the weight of the mice is 14.08 grams.
Step-by-step explanation:
(a)
The mean is given as follows:
Thus, the mean of the weight of the mice is 50.26 grams.
(b)
Compute the standard deviation as follows:
![s=\frac{1}{\sum f_{i}-1}[\sum f_{i}x_{i}^{2}-\frac{1}{\sum f_{i}}(\sum f_{i}x_{i})^{2}]](https://tex.z-dn.net/?f=s%3D%5Cfrac%7B1%7D%7B%5Csum%20f_%7Bi%7D-1%7D%5B%5Csum%20f_%7Bi%7Dx_%7Bi%7D%5E%7B2%7D-%5Cfrac%7B1%7D%7B%5Csum%20f_%7Bi%7D%7D%28%5Csum%20f_%7Bi%7Dx_%7Bi%7D%29%5E%7B2%7D%5D)
![=\frac{1}{100-1}[254001-\frac{1}{100}(5026)^{2}]\\\\=\frac{1}{99}\times 1394.24\\\\=14.08323\\\\\approx 14.08](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B100-1%7D%5B254001-%5Cfrac%7B1%7D%7B100%7D%285026%29%5E%7B2%7D%5D%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B99%7D%5Ctimes%201394.24%5C%5C%5C%5C%3D14.08323%5C%5C%5C%5C%5Capprox%2014.08)
Thus, the standard deviation of the weight of the mice is 14.08 grams.
