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3 years ago

Solve the proportion for n: 4.5/n = 27/37.8

Mathematics

1 answer:

djyliett [7]3 years ago

3 0

4.5 / n = 27 / 37.8
cross multiply
(27)(n) = (37.8)(4.5)
27n = 170.1
n = 170.1/27
n = 6.3 <==

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Iteru [2.4K]

Given:

The function for size of a square frame is

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The function for the price in dollars for the frame is

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To find:

The single function for the price of a picture with an edge length of x.

Solution:

We know that, for a picture with an edge length of x.

Size of a square frame = f(x)

Price in dollars for the frame = p(x)

Single function for the price of a picture with an edge length of x is

$(p\circ f)(x)=p(f(x))$

$(p\circ f)(x)=p(x+2)$ $[\because f(x)=x+2]$

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$c(x)=3(x+2)$

Therefore, the required function is $c(x)=3(x+2)$ .

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strojnjashka [21]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Suppose that the probability that any particle emitted by a radioactive material will penetrate a certain shield is 0.01. If 10

AnnyKZ [126]

Answer:

a)P=0.42

b) $n\geq 297$

Step-by-step explanation:

We have a binomial distribution, since the result of each experiment admits only two categories (success and failure) and the value of both possibilities is constant in all experiments. The probability of getting k successes in n trials is given by:

$P=\begin{pmatrix}n\\ k\end{pmatrix} p^k(1-p)^{n-k}=\frac{n!}{k!(n!-k!)}p^k(1-p)^{n-k}$

a) we have k=2, n=10 and p=0.01:

$P=\frac{10!}{2!(10!-2!)}0.01^2(1-0.01)^{10-2}\\P=\frac{10!}{2!*8!}0.01^2(0.99)^{8}\\P=45*0.01^2(0.99)^8=0.42$

b) We have, $1-(1-p)^n=P$ , Here P is the probability that at least one particle will penetrate the shield, this probabity has to be equal or greater than 0.95. Therefore, this will be equal to subtract from the total probability, the probability that the particles do not penetrate raised to the total number of particles.