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2 years ago

6

Aidens class is planning a fundraiser. The results show that 3 out of 4 students want to sell candy. If there are 28 students in

the class, how many want to sell candy?

2 answers:

Free_Kalibri [48]2 years ago

6 0

Answer:

21 students

Step-by-step explanation:

28÷4=7

3×7=21

Mice21 [21]2 years ago

3 0

21 students

Good luck hope it helps

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What is 12/7simplified

Citrus2011 [14]

The anwser to your question is 1 and 5/7

5 0

2 years ago

The planets move around the sun in elliptical orbits with the sun at one focus. The point in the orbit at which the planet is cl

gladu [14]

Consider the attached ellipse. Let the sun be at the right focus. Then perihelion is at right vertex on the x-axis and aphelion is at the left vertex on the x-axis.

The distances:

from perihelion to the sun in terms of ellipse is a-c;
from aphelion to the sun in terms of ellipse is a+c.

Then

$\left\{\begin{array}{l}a-c=741,000,000\\a+c=817,000,000\end{array}\right.$

Add these two equations:

$2a=1,558,000,000 \\ \\a=779,000,000$

and subtract first equation from the second:

$2c=76,000,000 \\ \\c=38,000,000.$

Note that $b=\sqrt{a^2-c^2},$ thus

$b=\sqrt{779,000,000^2-38,000,000^2}=\sqrt{605,397,000,000,000,000}.$

The equation for the planet's orbit is

$\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1\Rightarrow \dfrac{x^2}{606,841,000,000,000,000}+\dfrac{y^2}{605,397,000,000,000,000}=1.$

7 0

3 years ago

Kryger [21]

Answer:

£2112

Step-by-step explanation:

To find Gavin's share, sum the parts of the ratio, 4 + 1 = 5 parts

Divide the win by 5 to find the value of one part of the ratio.

£8800 ÷ 5 = £1760 ← value of 1 part of ratio, thus

4 parts = 4 × £1760 = £7040 ← Gavin's share

Now repeat the process with the ratio for his family

1 + 6 + 3 = 10 parts

£7040 ÷ 10 = £704 ← value of 1 part of the ratio, thus

6 × £704 = £4224 ← wife's share

3 × £704 = £2112 ← son's share

Difference = £4224 - £2112 = £2112

Thus his wife gets £2112 more than the son

4 0

3 years ago

I need help can anyone help me with this pls

Cerrena [4.2K]

It might be 2.5 but I could be wrong

3 0

2 years ago

There are three different cubes such that the first cube is 64 times the volume of the second, and the volume of the second cube

tankabanditka [31]

Answer:

4/3

Step-by-step explanation:

If the ratio between the volumes of the first and the second cube is 64, the ratio between the sides is the cubic root of the ratio between the volumes, so:

$V1 / V2 = 64$

$s1 / s2 = \sqrt[3]{64} = 4$

Doing the same for the second and third cubes, we have:

$V2 / V3 = 1/27$

$s2/ s3 = \sqrt[3]{1/27} = 1/3$

So the ratio of the first cube side and the third cube side is:

$s1 / s3 = (s1/s2) * (s2/s3) = 4 * (1/3) = 4/3$

5 0

2 years ago