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3 years ago

How many decimeters are there if there are 3 centimeters.

2 answers:

8 0

The answer would be 0.3 decimeters.
For every centimeter, there will be 0.1 decimeter.
Hope I could help.
Actually... I just did.

Shtirlitz [24]3 years ago

7 0

There are .3 decimeters in 3 centimeters

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A floor rug is rectangular in shape. The width of the rug is 2 ft less than its length. The perimeter of the rug is 36 ft.

Ganezh [65]

Answer

Perimeter of rectangle, P = 2L + 2W

P = 36ft

Width, W

Length, L = W + 2ft

Perimeter of rectangle, P = 2L + 2W

Given; P = 36ft

36ft = 2W + 2(W + 2ft)

36ft = 2W + 2W + 4ft

32ft = 4W

8ft = W

L = W + 2ft

L = 8ft + 2ft

L = 10ft

5 0

2 years ago

Read 2 more answers

A number that is much higher or much lower than the other numbers in a set of data is an ______________. (There are no options..

aleksklad [387]

I think is is called an outlier

4 0

3 years ago

Copy PQ to the line with an endpoint at R.

WITCHER [35]

Answer: Hello your question lacks some details attached below is the complete question

answer:

Place a compass at point Q ,
measure arc PQ
Draw an arc with the compass that is equal to PQ ,
Place the compass at point R ,
cut through the line to the left of R with the arc in compass,
Assume the new points to be P' and R be Q' , where P' Q' will become the new image of PQ with their end point will be R

Step-by-step explanation:

The steps required to draw an arc intersecting the line that will create a segment with length PQ are ;

Place a compass at point Q , measure arc PQ

Draw an arc with the compass that is equal to PQ , Place the compass at point R , cut through the line to the left of R with the arc in compass,

Assume the new points to be P' and R be Q' , where P' Q' will become the new image of PQ with their end point will be R

4 0

2 years ago

Given directed line segment QS , find the coordinates of R

Degger [83]

Answer:

The answer is below

Step-by-step explanation:

The question is not complete, what are the coordinates of point Q and R. But I would show how to solve this.

The location of a point O(x, y) which divides line segment AB in the ratio a:b with point A at ( $x_1,y_1$ ) and B( $x_2,y_2$ ) is given by the formula:

$x=\frac{a}{a+b}(x_2-x_1)+x_1\\ \\y=\frac{a}{a+b}(y_2-y_1)+y_1$

If point Q is at ( $x_1,y_1$ ) and S at ( $x_2,y_2$ ) and R(x, y) divides QS in the ratio QR to RS is 3:5, The coordinates of R is:

$x=\frac{3}{3+5}(x_2-x_1)+x_1=\frac{3}{8}(x_2-x_1)+x_1\\ \\y=\frac{3}{3+5}(y_2-y_1)+y_1=\frac{3}{8}(y_2-y_1)+y_1$

Let us assume Q(−9,4) and S(7,−4)

$x=\frac{3}{8}(7-(-9))+(-9)=\frac{3}{8}(16)-9=-3\\\\y=\frac{3}{8}(-4-4)+4=\frac{3}{8}(-8)+4=1$

4 0

3 years ago

A line contains the points (-3, 4) and (7, -1). Calculate the equation of the line in the form

ad-work [718]

Answer:

$y=-\frac{1}{2}x+\frac{5}{2}$

Step-by-step explanation:

First we need to find the slope of the line. We can plug in both coordinates in to the slope formula.

The slope formula is:

$m=\frac{y2-y1}{x2-x1}$

So I will use (-3,4) as the first coordinate, and (7,-1) as the second coordinate.

x₁ = -3

y₁ = 4

x₂ = 7

y₂= -1

I will plug in these values to find the slope.

$m=\frac{y2-y1}{x2-x1}\\\\m=\frac{-1-4}{7-(-3)}\\\\m=\frac{-5}{10}\\\\m=-\frac{1}{2}$

Now that we know the slope is -1/2, we can plug in the slope and a point into the point slope equation. Then we can solve for y.

$y-y_{1} =m(x-x_{1} )\\\\y-4==-\frac{1}{2}(x-(-3))\\\\y-4=-\frac{1}{2}x-\frac{3}{2}\\\\ y=-\frac{1}{2}x+\frac{5}{2}$

I have attached an image of what this graph should look like. Since the slope is -1/2, the y value should decrease by 1/2 every time you move over by 1 on the x axis. And since the equation says "+5/2" we know we have to shift the graph up by 5/2. The y-intercept will be 5/2.

I added another image that shows how to graph an equation using the equation y=mx+b

5 0

3 years ago