Answer:
what do you have to do this?
Step-by-step explanation:
what grade and type of math is this?
I only could find part of the triangle sorry, but u1 is 2 radical 2
Answer: 18 ≤ 6*S ≤ 30
Where S is the number of salmon fillets in one single package.
Step-by-step explanation:
Let's define S as the number of salmon fillets in one package.
We know that it contains at least 3, and no more than 5, then we can write:
3 ≤ S ≤ 5
Now we want to know the total number of salmon fillets that could be on 6 packages, then if S is the number of salmon fillets in one package, 6*S will e the number of salmon fillets in 6 packages.
We can find this by multiplying the inequality:
3 ≤ S ≤ 5
by 6.
We get:
6*3 ≤ 6*S ≤ 6*5
18 ≤ 6*S ≤ 30
Then in 6 packages, we could have any number between 18 and 30 fillets of salmon.
Answer:
25,600
Step-by-step explanation:
You can use the rule of three considering that the number of dolls sold varies directly with the advertising budget:
$54,000 → 9,600
$144,000 → x

x=25,600
According to this, the number of dolls sold if the amount of advertising budget is increased to $144,000 is 25,600.
Check the picture below, so it reaches the maximum height at the vertex, let's check where that is
![h(t)=64t-16t^2+0 \\\\[-0.35em] ~\dotfill\\\\ \textit{vertex of a vertical parabola, using coefficients} \\\\ h(t)=\stackrel{\stackrel{a}{\downarrow }}{-16}t^2\stackrel{\stackrel{b}{\downarrow }}{+64}t\stackrel{\stackrel{c}{\downarrow }}{+0} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{ 64}{2(-16)}~~~~ ,~~~~ 0-\cfrac{ (64)^2}{4(-16)}\right)\implies \stackrel{maximum~height}{(2~~,~~\stackrel{\downarrow }{64})}](https://tex.z-dn.net/?f=h%28t%29%3D64t-16t%5E2%2B0%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ctextit%7Bvertex%20of%20a%20vertical%20parabola%2C%20using%20coefficients%7D%20%5C%5C%5C%5C%20h%28t%29%3D%5Cstackrel%7B%5Cstackrel%7Ba%7D%7B%5Cdownarrow%20%7D%7D%7B-16%7Dt%5E2%5Cstackrel%7B%5Cstackrel%7Bb%7D%7B%5Cdownarrow%20%7D%7D%7B%2B64%7Dt%5Cstackrel%7B%5Cstackrel%7Bc%7D%7B%5Cdownarrow%20%7D%7D%7B%2B0%7D%20%5Cqquad%20%5Cqquad%20%5Cleft%28-%5Ccfrac%7B%20b%7D%7B2%20a%7D~~~~%20%2C~~~~%20c-%5Ccfrac%7B%20b%5E2%7D%7B4%20a%7D%5Cright%29%20%5C%5C%5C%5C%5C%5C%20%5Cleft%28-%5Ccfrac%7B%2064%7D%7B2%28-16%29%7D~~~~%20%2C~~~~%200-%5Ccfrac%7B%20%2864%29%5E2%7D%7B4%28-16%29%7D%5Cright%29%5Cimplies%20%5Cstackrel%7Bmaximum~height%7D%7B%282~~%2C~~%5Cstackrel%7B%5Cdownarrow%20%7D%7B64%7D%29%7D)