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vichka [17]
3 years ago
9

7. Patrick tosses a penny and a number cube, with faces numbered 1 through 6, at the

Mathematics
1 answer:
lions [1.4K]3 years ago
7 0

Answer:

B. 1/3 or 33.3%

Step-by-step explanation:

<em>H-</em> 1 ,2 ,3, 4, 5, 6

<em>T-</em> 1, 2, 3, 4, 5, 6

Multiples of <em>3:</em> 3, 6, 9, 12, etc..

<em>2/6 simplified is 1/3 </em>

So, the probability that the penny will land on heads and the number cube will land on a multiple of 3, is 1/3 or 33.3%

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The shortest side of a polygon of area 196 sq. in. is 4 in. long. Find the area of a similar polygon whose shortest side is 8 in
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The correct answer is:  " 784 in² " . 
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                  {or; write as:  " 784 sq. inches " .}.
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      When the side is doubled (in this case, 4 is doubled; 4 * 2 = 8} ; the area is increased by 2² times; that is, by 4 times;  so, the area is:
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3 years ago
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5. The recursive algorithm given below can be used to compute gcd(a, b) where a and b are non-negative integer, not both zero.
s2008m [1.1K]

Implementating the given algorithm in python 3, the greatest common divisors of <em>(</em><em>124</em><em> </em><em>and</em><em> </em><em>244</em><em>)</em><em> </em>and <em>(</em><em>4424</em><em> </em><em>and</em><em> </em><em>2111</em><em>)</em><em> </em>are 4 and 1 respectively.

The program implementation is given below and the output of the sample run is attached.

def gcd(a, b):

<em>#initialize</em><em> </em><em>a</em><em> </em><em>function</em><em> </em><em>named</em><em> </em><em>gcd</em><em> </em><em>which</em><em> </em><em>takes</em><em> </em><em>in</em><em> </em><em>two</em><em> </em><em>parameters</em><em> </em>

if a>b:

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>greater</em><em> </em><em>than</em><em> </em><em>b</em>

return gcd (b, a)

<em>#if</em><em> </em><em>true</em><em> </em><em>interchange</em><em> </em><em>the</em><em> </em><em>Parameters</em><em> </em><em>and</em><em> </em><em>Recall</em><em> </em><em>the</em><em> </em><em>function</em><em> </em>

elif a == 0:

return b

elif a == 1:

return 1

elif((a%2 == 0)and(b%2==0)):

<em>#even</em><em> </em><em>numbers</em><em> </em><em>leave</em><em> </em><em>no</em><em> </em><em>remainder</em><em> </em><em>when</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>2</em><em>,</em><em> </em><em>checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>and</em><em> </em><em>b</em><em> </em><em>are</em><em> </em><em>even</em><em> </em>

return 2 * gcd(a/2, b/2)

elif((a%2 !=0) and (b%2==0)):

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>odd</em><em> </em><em>and</em><em> </em><em>B</em><em> </em><em>is</em><em> </em><em>even</em><em> </em>

return gcd(a, b/2)

else :

return gcd(a, b-a)

<em>#since</em><em> </em><em>it's</em><em> </em><em>a</em><em> </em><em>recursive</em><em> </em><em>function</em><em>,</em><em> </em><em>it</em><em> </em><em>recalls</em><em> </em><em>the function</em><em> </em><em>with </em><em>new</em><em> </em><em>parameters</em><em> </em><em>until</em><em> </em><em>a</em><em> </em><em>certain</em><em> </em><em>condition</em><em> </em><em>is</em><em> </em><em>satisfied</em><em> </em>

print(gcd(124, 244))

print()

<em>#leaves</em><em> </em><em>a</em><em> </em><em>space</em><em> </em><em>after</em><em> </em><em>the</em><em> </em><em>first</em><em> </em><em>output</em><em> </em>

print(gcd(4424, 2111))

Learn more :brainly.com/question/25506437

6 0
3 years ago
an aquarium has a ratio of 5 rays for every 3 sharks. What percent of this grouping of animals are rays
sashaice [31]

Answer:

62.5%

Step-by-step explanation:

Total number of animals in a group= 5+3=8 animals

Number of rays=5

Since we only have 5 rays out of the total 8, to express the number of rays as a percentage of the total animals, we divide the number of rays by the total animals then multiply by 100 to express in percentage as needed in the question

Percentage of rays=\frac {5}{8}\times 100=62.5

Therefore, the percentage is 62.5%

6 0
3 years ago
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