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gizmo_the_mogwai [7]
3 years ago
5

PLEASE HELP ASAPPPPPPPP

Mathematics
2 answers:
Sauron [17]3 years ago
8 0
It would be D.
h4 x 3 = 12 x 6 = 72
soo its h72
hope this helps
levacccp [35]3 years ago
7 0
= h^4 (h^-18)
= h^-14
= 1/h^14

answer  is C. 1/h^14
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The sum of two consecutive integers is 345. What are the integers? need help with it
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Answer:

hi there ☺️

Here we will use algebra to find three consecutive integers whose sum is 345. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 345. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 345

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 345

3X + 3 = 345

3X + 3 - 3 = 345 - 3

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Which means that the first number is 114, the second number is 114 + 1 and the third number is 114 + 2. Therefore, three consecutive integers that add up to 345 are 114, 115, and 116.

114 + 115 + 116 = 345

We know our answer is correct because 114 + 115 + 116 equals 345 as displayed above.

Step-by-step explanation:

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