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BlackZzzverrR [31]
3 years ago
10

I need help factoring polynomial 3h9^-192h^6. I don't know where to begin.

Mathematics
1 answer:
Elden [556K]3 years ago
7 0
First, pull out the GCM from the two terms: 3x^6(x^3-64)
Then factor the remains using the difference of cubes: 3x^6(x-4)(x^2+4x+16)
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Consider this equation:
aleksandrvk [35]

Answer:

  • Plan: separate the variable term from the constant term; divide by the coefficient of the variable.
  • Steps: add 4 to both sides; collect terms; divide both sides by 3.

Step-by-step explanation:

The first step is to look a the equation to see where the variable is in relation to the equal sign, and whether there are any constants on that same side of the equal sign.

Here, the variable terms are on the left, and there is a constant there, as well. The plan for solving the equation is to eliminate the constant that is on the same side of the equation as the variable, then divide by the coefficient of the variable. To find that coefficient, we need to collect terms. In summary, the plan is to ...

  • add 4 to both sides of the equation
  • collect terms
  • divide by the coefficient of the variable (3)

Executing that plan, the steps are ...

  -2x -4 +5x +4 = 8 +4 . . . . add 4

  3x = 12 . . . . . . . . . . . . . . . collect terms

  x = 4 . . . . . . . . . divide by 3

4 0
3 years ago
How to solve this system of equal: x+y+z=1;x^2+y^2+z^2=1
swat32

There are infinitely many solutions.

Algebraically, we can eliminate z and try to solve for x,y:

x+y+z=1\implies z=1-x-y

Then

x^2+y^2+(1-x-y)^2=1

\implies x^2+y^2+1-2x+x^2-2y+y^2+2xy=1

\implies x^2-x+y^2-y+xy=0

which is the equation of an ellipse.

5 0
4 years ago
Which strategy best explains how to solve this problem?
Rufina [12.5K]
This is a geometric sequence because each term is twice the value of the previous term.  So this is what would be called the common ratio, which in this case is 2.  Any geometric sequence can be expressed as:

a(n)=ar^(n-1), a(n)=nth value, a=initial value, r=common ratio, n=term number

In this case we have r=2 and a=1 so

a(n)=2^(n-1)  so on the sixth week he will run:

a(6)=2^5=32

He will run 32 blocks by the end of the sixth week.

Now if you wanted to know the total amount he runs in the six weeks, you need the sum of the terms and the sum of a geometric sequence is:

s(n)=a(1-r^n)/(1-r)  where the variables have the same values so

s(n)=(1-2^n)/(1-2)

s(n)=2^n-1 so 

s(6)=2^6-1

s(6)=64-1

s(6)=63 blocks

So he would run a total of 63 blocks in the six weeks.
4 0
3 years ago
Read 2 more answers
Tickets for seniors prom cost $25 for individual tickets and $40 for couples tickets. They collected a total of 2500 from ticket
quester [9]

Answer: 20

Step-by-step explanation:

Given

The cost of an individual ticket is $25

The cost of a couple's ticket is $40

The total sale is $2500

total ticket sold is 70

Suppose there are x individuals and y couples

\therefore x+y=70\quad \ldots(i)\\\\25x+40y=2500\quad \ldots(ii)\\\text{Solving }(i)\ \text{and}\ (ii)\ \text{we get}

x=20,y=50

So, they sold 20 tickets of the individual.

8 0
3 years ago
The Carter Motor Company claims that its new sedan, the Libra, will average better than 31 miles per gallon in the city. Assumin
Nutka1998 [239]

Answer:

The null hypothesis   H_o :  \mu =  31

The alternative hypothesis H_a :  \mu >  31

Step-by-step explanation:

From the question we are told that

  The population mean is  \mu =  31 \  miles / gallon

Generally

   The null hypothesis is that the company's  new sedan, the Libra, will have an average of   \mu =  31 \  miles / gallon

This mathematically  represented as

The null hypothesis   H_o :  \mu =  31

   The alternative hypothesis is that the company's  new sedan, the Libra, will have an average better than   \mu =  31 \  miles / gallon

This mathematically  represented as

     The alternative hypothesis H_a :  \mu >  31

7 0
3 years ago
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